The area of a parallelogram is calculated using the formula:
$ \text{Area} = \text{Base} \times \text{Height} $
Consider two parallelograms, Parallelogram 1 and Parallelogram 2.
Using the area formula:
Since $ \text{Base}_1 = \text{Base}_2 $ and $ \text{Height}_1 = \text{Height}_2 $, it follows that:
$ \text{Area}_1 = \text{Area}_2 $
The ratio of their areas is:
$ \frac{\text{Area}_1}{\text{Area}_2} = \frac{\text{Area}_1}{\text{Area}_1} = \frac{1}{1} $
Therefore, the ratio of the areas is $ 1 : 1 $.
If length of a rectangle is increased to its three times and breadth is decreased to its half, then the ratio of the area of given rectangle to the area of new rectangle is:
The width of the path around a square field is 4.5 m and its area is 105.75 m 2. Find the cost of fencing the field at the rate of Rs. 100 per meter.
What is the area of the square (in cm 2) whose vertices lie on a circle of radius 5 cm?
The circumcentre of an equilateral triangle is at a distance of 3.2 cm from the base of the triangle. What is the length (in cm) of each of its altitudes?
The perimeter of a circular lawn is 1232 m. There is 7 m wide path around the lawn. The area (in m 2) of the path is:
Take \(\left(\pi=\frac{22}{7}\right)\)