The problem provides the perimeter of a square and asks for its area.
Given: Perimeter of the square, $P = 20 \text{ cm}$.
The perimeter of a square is calculated using the formula:
$P = 4s$
where $s$ is the length of one side of the square.
We can find the side length ($s$) by rearranging the formula:
$s = \frac{P}{4}$
Calculate the side length:
Substitute the given perimeter into the formula:
$s = \frac{20 \text{ cm}}{4}$
$s = 5 \text{ cm}$
Calculate the area:
The area of a square is calculated using the formula:
$A = s^2$
Substitute the calculated side length into the area formula:
$A = (5 \text{ cm})^2$
$A = 25 \text{ cm}^2$
Therefore, the area of the square is $25 \text{ cm}^2$. This matches Option 3.
The sum of all interior angles of a regular polygon is 1800°. How many diagonals does the polygon have?
The difference between the measure of an interior angle and an exterior angle of a regular polygon is 100°. What is the number of sides of the polygon?
If the area of a square is 625 cm 2, then what is the perimeter of the square?
The area and the perimeter of a sheet of paper are 240 cm 2and 68 cm, respectively. What would be its length and breadth?
One side of rectangular field is 15 meters and one of its diagonals is 17 meters. Then find the area of the field.
The bisector of ∠B in ΔABC meets AC at D. If AB = 12 cm, BC = 18 cm and AC = 15 cm, then the length of AD (in cm) is:
The perimeter and the length of one of the diagonals of a rhombus is 26 cm and 5 cm respectively. Find the length of its other diagonal (in cm).