The problem provides the perimeter of a square and asks for its area.
Given: Perimeter of the square, $P = 20 \text{ cm}$.
The perimeter of a square is calculated using the formula:
$P = 4s$
where $s$ is the length of one side of the square.
We can find the side length ($s$) by rearranging the formula:
$s = \frac{P}{4}$
Calculate the side length:
Substitute the given perimeter into the formula:
$s = \frac{20 \text{ cm}}{4}$
$s = 5 \text{ cm}$
Calculate the area:
The area of a square is calculated using the formula:
$A = s^2$
Substitute the calculated side length into the area formula:
$A = (5 \text{ cm})^2$
$A = 25 \text{ cm}^2$
Therefore, the area of the square is $25 \text{ cm}^2$. This matches Option 3.
If length of a rectangle is increased to its three times and breadth is decreased to its half, then the ratio of the area of given rectangle to the area of new rectangle is:
The width of the path around a square field is 4.5 m and its area is 105.75 m 2. Find the cost of fencing the field at the rate of Rs. 100 per meter.
What is the area of the square (in cm 2) whose vertices lie on a circle of radius 5 cm?
The circumcentre of an equilateral triangle is at a distance of 3.2 cm from the base of the triangle. What is the length (in cm) of each of its altitudes?
The perimeter of a circular lawn is 1232 m. There is 7 m wide path around the lawn. The area (in m 2) of the path is:
Take \(\left(\pi=\frac{22}{7}\right)\)