The question asks for the area of the greatest circle that can fit inside a square with a side length of 21 cm.
The largest possible circle that can be inscribed within a square will have a diameter equal to the side length of the square.
The radius ($r$) is half the diameter ($d$).
Calculation: $r = \frac{d}{2} = \frac{21 \text{ cm}}{2} = 10.5$ cm.
The formula for the area ($A$) of a circle is $A = \pi r^2$. We use the approximation $\pi \approx \frac{22}{7}$.
Calculation: $A = \pi r^2$ $A = \frac{22}{7} \times (10.5 \text{ cm})^2$ $A = \frac{22}{7} \times (\frac{21}{2} \text{ cm})^2$ $A = \frac{22}{7} \times \frac{441}{4} \text{ cm}^2$ $A = \frac{11 \times 441}{7 \times 2} \text{ cm}^2$ $A = \frac{11 \times 63}{2} \text{ cm}^2$ $A = \frac{693}{2} \text{ cm}^2$ $A = 346.5 \text{ cm}^2$
Therefore, the area of the greatest circle that can be inscribed inside the square is 346.5 cm$^2$.
If length of a rectangle is increased to its three times and breadth is decreased to its half, then the ratio of the area of given rectangle to the area of new rectangle is:
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Take \(\left(\pi=\frac{22}{7}\right)\)