The question asks for the area of the greatest circle that can fit inside a square with a side length of 21 cm.
The largest possible circle that can be inscribed within a square will have a diameter equal to the side length of the square.
The radius ($r$) is half the diameter ($d$).
Calculation: $r = \frac{d}{2} = \frac{21 \text{ cm}}{2} = 10.5$ cm.
The formula for the area ($A$) of a circle is $A = \pi r^2$. We use the approximation $\pi \approx \frac{22}{7}$.
Calculation: $A = \pi r^2$ $A = \frac{22}{7} \times (10.5 \text{ cm})^2$ $A = \frac{22}{7} \times (\frac{21}{2} \text{ cm})^2$ $A = \frac{22}{7} \times \frac{441}{4} \text{ cm}^2$ $A = \frac{11 \times 441}{7 \times 2} \text{ cm}^2$ $A = \frac{11 \times 63}{2} \text{ cm}^2$ $A = \frac{693}{2} \text{ cm}^2$ $A = 346.5 \text{ cm}^2$
Therefore, the area of the greatest circle that can be inscribed inside the square is 346.5 cm$^2$.
The sum of all interior angles of a regular polygon is 1800°. How many diagonals does the polygon have?
The difference between the measure of an interior angle and an exterior angle of a regular polygon is 100°. What is the number of sides of the polygon?
If the area of a square is 625 cm 2, then what is the perimeter of the square?
The perimeter of a semi circle is 25.7 cm. What is its diameter (in cm)? (π = 3.14)
The area of an isosceles right angled triangle is 121 cm 2. Find its hypotenuse.
Two sides of a triangle are of length 5 cm and 1.5 cm. The length of third side of the triangle cannot be