To determine the measure of the fifth angle in a pentagon, we utilize the property concerning the sum of its interior angles.
The total sum of the interior angles for any polygon can be calculated using the formula:
Sum = $(n-2) \times 180^\circ$
where $n$ represents the number of sides of the polygon.
A pentagon has 5 sides, so $n=5$. Plugging this into the formula gives the sum of its interior angles:
Sum = $(5-2) \times 180^\circ = 3 \times 180^\circ = 540^\circ$
The problem provides four angles of the pentagon:
Let the unknown fifth angle be represented by $x$. The sum of the four known angles is:
$70^\circ + 110^\circ + 135^\circ + 95^\circ = 410^\circ$
The sum of all five interior angles must equal $540^\circ$. Therefore, we can write the equation:
$410^\circ + x = 540^\circ$
To find the value of $x$, we isolate it:
$x = 540^\circ - 410^\circ$
$x = 130^\circ$
Thus, the measure of the fifth angle of the pentagon is $130^\circ$.
If length of a rectangle is increased to its three times and breadth is decreased to its half, then the ratio of the area of given rectangle to the area of new rectangle is:
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What is the area of the square (in cm 2) whose vertices lie on a circle of radius 5 cm?
The circumcentre of an equilateral triangle is at a distance of 3.2 cm from the base of the triangle. What is the length (in cm) of each of its altitudes?
The perimeter of a circular lawn is 1232 m. There is 7 m wide path around the lawn. The area (in m 2) of the path is:
Take \(\left(\pi=\frac{22}{7}\right)\)