To determine the measure of the fifth angle in a pentagon, we utilize the property concerning the sum of its interior angles.
The total sum of the interior angles for any polygon can be calculated using the formula:
Sum = $(n-2) \times 180^\circ$
where $n$ represents the number of sides of the polygon.
A pentagon has 5 sides, so $n=5$. Plugging this into the formula gives the sum of its interior angles:
Sum = $(5-2) \times 180^\circ = 3 \times 180^\circ = 540^\circ$
The problem provides four angles of the pentagon:
Let the unknown fifth angle be represented by $x$. The sum of the four known angles is:
$70^\circ + 110^\circ + 135^\circ + 95^\circ = 410^\circ$
The sum of all five interior angles must equal $540^\circ$. Therefore, we can write the equation:
$410^\circ + x = 540^\circ$
To find the value of $x$, we isolate it:
$x = 540^\circ - 410^\circ$
$x = 130^\circ$
Thus, the measure of the fifth angle of the pentagon is $130^\circ$.
The sum of all interior angles of a regular polygon is 1800°. How many diagonals does the polygon have?
The difference between the measure of an interior angle and an exterior angle of a regular polygon is 100°. What is the number of sides of the polygon?
If the area of a square is 625 cm 2, then what is the perimeter of the square?
The area and the perimeter of a sheet of paper are 240 cm 2and 68 cm, respectively. What would be its length and breadth?
One side of rectangular field is 15 meters and one of its diagonals is 17 meters. Then find the area of the field.
The bisector of ∠B in ΔABC meets AC at D. If AB = 12 cm, BC = 18 cm and AC = 15 cm, then the length of AD (in cm) is:
The perimeter and the length of one of the diagonals of a rhombus is 26 cm and 5 cm respectively. Find the length of its other diagonal (in cm).