The dimensions of the rectangular hall floor are given:
The area of the hall floor is calculated as:
$Areahall = $L_{hall} \times B_{hall} = 30 \text{ m} \times 24 \text{ m} = 720 \text{ m}^2$
The dimensions of each carpet are:
The area of one carpet is calculated as:
$Areacarpet = $L_{carpet} \times B_{carpet} = 6 \text{ m} \times 4 \text{ m} = 24 \text{ m}^2$
To find the total number of carpets needed to cover the hall floor, divide the total area of the floor by the area of a single carpet.
$Number of carpets = $\frac{\text{Area}_{hall}}{\text{Area}_{carpet}}$
$Number of carpets = $\frac{720 \text{ m}^2}{24 \text{ m}^2} = 30$
Therefore, 30 carpets are required to cover the floor.
If length of a rectangle is increased to its three times and breadth is decreased to its half, then the ratio of the area of given rectangle to the area of new rectangle is:
The width of the path around a square field is 4.5 m and its area is 105.75 m 2. Find the cost of fencing the field at the rate of Rs. 100 per meter.
What is the area of the square (in cm 2) whose vertices lie on a circle of radius 5 cm?
The circumcentre of an equilateral triangle is at a distance of 3.2 cm from the base of the triangle. What is the length (in cm) of each of its altitudes?
The perimeter of a circular lawn is 1232 m. There is 7 m wide path around the lawn. The area (in m 2) of the path is:
Take \(\left(\pi=\frac{22}{7}\right)\)