Let the radii of the two circles be \(r_1\) and \(r_2\). The problem states their ratio is \(4:3\). We can represent these radii using a variable, say \(x\), such that \(r_1 = 4x\) and \(r_2 = 3x\). This representation aligns with the polynomial forms in the options.
The area of a circle is given by the formula \(A = \pi r^2\). We need to find the area for each circle and then sum them.
The combined total surface area (\(A_{total}\)) is the sum of the individual areas:
\(A_{total} = A_1 + A_2\)
Substituting the calculated areas:
\(A_{total} = 16\pi x^2 + 9\pi x^2\)
Combine the terms:
\(A_{total} = (16 + 9)\pi x^2\)
\(A_{total} = 25\pi x^2\)
This polynomial expression represents the combined total surface area of the two circles.
What is the remainder of function $4a^3 - 12a^2 + 14a - 3$ when it is divided by \(\frac{a-1}{2}\)?