To find the zeros of the quadratic polynomial $x^2 - 2x - 15$, we need to find the values of $x$ for which the polynomial equals zero. This means solving the equation:
$x^2 - 2x - 15 = 0$
We can solve this quadratic equation by factoring the expression $x^2 - 2x - 15$. We look for two numbers that:
The pairs of factors for -15 are: (1, -15), (-1, 15), (3, -5), and (-3, 5). Let's check their sums:
The pair (3, -5) adds up to -2. Therefore, we can factor the quadratic polynomial as:
$ (x + 3)(x - 5) = 0 $
For the product of two factors to be zero, at least one of the factors must be zero. So, we set each factor equal to zero and solve for $x$:
$x + 3 = 0$
$x = -3$
$x - 5 = 0$
$x = 5$
The zeros of the quadratic polynomial $x^2 - 2x - 15$ are -3 and 5.
What is the remainder of function $4a^3 - 12a^2 + 14a - 3$ when it is divided by \(\frac{a-1}{2}\)?