Two cabs A and B start from C for town D. If the distance between the two towns is 540 km and the slower taxi travelling at an average speed of 90 km/hr takes an hour more than the faster taxi, then find the speed (in km/hr) of the faster taxi.
108
This problem involves calculating the speed of a faster taxi given the distance, the speed of a slower taxi, and the difference in their travel times. We can use the relationship between speed, distance, and time to solve this.
We are given the following details:
Let \(S_B\) be the speed of the faster taxi in km/hr, \(T_A\) be the time taken by the slower taxi in hours, and \(T_B\) be the time taken by the faster taxi in hours.
From the problem, we know that \(T_A = T_B + 1\).
The basic formula relating speed, distance, and time is:
\(\text{Speed} = \frac{\text{Distance}}{\text{Time}}\)
Rearranging this, we get the formula for time:
\(\text{Time} = \frac{\text{Distance}}{\text{Speed}}\)
Using the formula, we can calculate the time taken by the slower taxi (\(T_A\)):
\(T_A = \frac{D}{S_A}\)
Substituting the given values:
\(T_A = \frac{540 \text{ km}}{90 \text{ km/hr}}\)
$T_A = 6 \text{ hours}
So, the slower taxi takes 6 hours to cover the 540 km distance.
We know that the slower taxi takes 1 hour more than the faster taxi. So, the time taken by the faster taxi (\(T_B\)) is:
\(T_B = T_A - 1\)
\(T_B = 6 \text{ hours} - 1 \text{ hour}\)
\(T_B = 5 \text{ hours}\)
Now, we can express the time taken by the faster taxi using its speed \(S_B\) and the distance \(D\):
\(T_B = \frac{D}{S_B}\)
Substitute the known values into this equation:
\(5 \text{ hours} = \frac{540 \text{ km}}{S_B}\)
To find \(S_B\), we can rearrange the equation:
\(S_B = \frac{540 \text{ km}}{5 \text{ hours}}\)
Performing the division:
$S_B = 108 \text{ km/hr}
The speed of the faster taxi is 108 km/hr.
Let's compare our calculated speed with the given options:
Our calculated speed of 108 km/hr matches Option 3.
Here is a summary of the formulas used in speed, distance, and time problems:
| Concept | Formula | Units (e.g., km, hr, km/hr) |
|---|---|---|
| Speed | \(\text{Speed} = \frac{\text{Distance}}{\text{Time}}\) | km/hr, m/s, miles/hr, etc. |
| Distance | \(\text{Distance} = \text{Speed} \times \text{Time}\) | km, meters, miles, etc. |
| Time | \(\text{Time} = \frac{\text{Distance}}{\text{Speed}}\) | hours, seconds, minutes, etc. |
Problems involving speed, distance, and time often appear in competitive exams. Understanding the basic formulas is crucial. Other variations include:
Practice with different types of problems helps in mastering this topic.
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