The problem asks us to find the ratio of metals A and B in a final mixture formed by melting and mixing equal quantities of two different alloys.
To simplify calculations, let's assume we take a quantity of each alloy that is a multiple of the sum of their ratio parts. The sums are (3+2=5) for Alloy 1 and (5+3=8) for Alloy 2. The least common multiple (LCM) of 5 and 8 is 40.
Let's assume we take 40 units of Alloy 1 and 40 units of Alloy 2.
When these equal quantities (40 units each) are mixed, the total amounts of metals A and B in the final mixture are:
Therefore, the ratio of metals A and B in the final mixture is 49 : 31.
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