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Question

To a number, $(\frac{1}{3} - \frac{1}{4})$ is added. From the sum so obtained $\frac{1}{3}$ of $\frac{1}{4}$ is subtracted and the remainder is $\frac{1}{3} + \frac{1}{4}$. Find the number.

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$\frac{7}{12}$

Number Calculation: Solving Fraction Problems

Let the unknown number be represented by $x$. We will translate the problem statement into a mathematical equation and solve for $x$.

Step 1: Initial Fraction Operations

First, calculate the values of the fractional expressions given in the problem.

  • Calculate the difference: $ \frac{1}{3} - \frac{1}{4} = \frac{4}{12} - \frac{3}{12} = \frac{1}{12} $
  • Calculate the product ($\frac{1}{3}$ of $\frac{1}{4}$): $ \frac{1}{3} \times \frac{1}{4} = \frac{1}{12} $
  • Calculate the target remainder sum: $ \frac{1}{3} + \frac{1}{4} = \frac{4}{12} + \frac{3}{12} = \frac{7}{12} $

Step 2: Formulate the Algebraic Equation

Now, construct the equation based on the problem description.

The problem states that to the number ($x$), $(\frac{1}{3} - \frac{1}{4})$ is added. From this sum, $\frac{1}{3}$ of $\frac{1}{4}$ is subtracted, and the result is $\frac{1}{3} + \frac{1}{4}$.

Using the calculated values:

$ (x + \frac{1}{12}) - \frac{1}{12} = \frac{7}{12} $

Step 3: Solve for the Unknown Number

Simplify the equation to find the value of $x$.

The equation simplifies as follows:

$ x + (\frac{1}{12} - \frac{1}{12}) = \frac{7}{12} $ $ x + 0 = \frac{7}{12} $ $ x = \frac{7}{12} $

The number is $\frac{7}{12}$.

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Important Questions from Simplification

  1. Simplify

    6 × {28 ÷ 84 × {36 × 49 ÷ (6 × 7)}}.

  2. Simplify.

  3. A bag contains ₹5, 2 and 1 coins in the ratio of 3 : 4 : 5. The total value of all the coins is ₹2,100. How many coins of ₹5 are there in the bag?
  4. \(\frac{6}{2}\times\frac{10}{2}\div\frac{6}{2}\times6^2+5\times4=?\)
  5. Find the value of 2.\(\overline {36} \) + 3.\(\overline {21} \) - 1.\(\overline {05} \)
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