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Question

The value of $\frac{\{(13)^3 - 4^3\}}{13 - 8 \div 2} \div 8 - \{2 + 6 \times 9\}$ is:

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$-\frac{211}{8}$

Evaluating Arithmetic Expression Step-by-Step

The problem asks to evaluate the expression: $\frac{\{(13)^3 - 4^3\}}{13 - 8 \div 2} \div 8 - \{2 + 6 \times 9\}$. We need to follow the order of operations (BODMAS/PEMDAS: Brackets/Parentheses, Orders/Exponents, Division and Multiplication, Addition and Subtraction).

Numerator Calculation: Exponents and Subtraction

  • Calculate the powers: $13^3 = 2197$ and $4^3 = 64$.
  • Subtract the results: $2197 - 64 = 2133$.

Denominator Calculation: Division and Subtraction

  • Perform division first: $8 \div 2 = 4$.
  • Perform subtraction: $13 - 4 = 9$.

First Fraction Simplification

  • Divide the numerator by the denominator: $\frac{2133}{9} = 237$.

Brackets Calculation: Multiplication and Addition

  • Perform multiplication inside the braces: $6 \times 9 = 54$.
  • Perform addition: $2 + 54 = 56$.

Combining Operations: Division and Final Subtraction

  • The expression is now: $237 \div 8 - 56$.
  • Perform the division: $237 \div 8 = \frac{237}{8}$.
  • Convert 56 to a fraction with denominator 8: $56 = \frac{56 \times 8}{8} = \frac{448}{8}$.
  • Perform the final subtraction: $\frac{237}{8} - \frac{448}{8} = \frac{237 - 448}{8}$.
  • Calculate the final result: $\frac{-211}{8}$.

The final value of the expression is $-\frac{211}{8}$.

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