$\frac{81}{7} \times \frac{21}{3} - 4\frac{2}{3} \div \frac{7}{9} \times \frac{121}{6}$
The problem requires calculating the value of the expression $\frac{81}{7} \times \frac{21}{3} - 4\frac{2}{3} \div \frac{7}{9} \times \frac{121}{6}$. We follow the order of operations (BODMAS/PEMDAS): Brackets/Parentheses, Orders/Exponents, Division and Multiplication (from left to right), Addition and Subtraction (from left to right).
First, convert the mixed number $4\frac{2}{3}$ into an improper fraction:
$4\frac{2}{3} = \frac{(4 \times 3) + 2}{3} = \frac{12 + 2}{3} = \frac{14}{3}$
Next, perform the division operation:
$\frac{14}{3} \div \frac{7}{9} = \frac{14}{3} \times \frac{9}{7}$
Simplify the terms:
$\frac{14}{7} \times \frac{9}{3} = 2 \times 3 = 6$
Now, perform the multiplication operations from left to right.
First multiplication:
$\frac{81}{7} \times \frac{21}{3} = \frac{81}{3} \times \frac{21}{7} = 27 \times 3 = 81$
Second multiplication (using the result from Step 2):
$6 \times \frac{121}{6}$
Simplify the terms:
$6 \times \frac{121}{6} = 121$
Finally, perform the subtraction using the results from the multiplication steps:
$81 - 121 = -40$
The value of the expression $\frac{81}{7} \times \frac{21}{3} - 4\frac{2}{3} \div \frac{7}{9} \times \frac{121}{6}$ is -40.
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