Three years ago, the age of a person was six times the age of his younger brother. Eight years later, the age of the person will be three years less than twice the age of his younger brother. Find the present ages of the person and his younger brother.
15 years and 5 years
Step 1 – Variables (taking the marked-answer pair person=15, brother=5): Three years ago person=12, brother=2; person was 6× brother. ✓
Step 2 – Verify second condition: Eight years later person=23, brother=13; twice brother − 3 = 23. ✓
Hence person=15 yrs, brother=5 yrs, option 4.
One year ago, the age of B was twice that of A. After 9 years, if the ratio of the ages of B and A would be 4 : 3, then the sum of their present ages is ____ years.
A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years. Then what is the present age of the wife?
The average age of a husband and his wife was 20 years at the time of their marriage. After 6 years, they have a 2 -year old child. Find the present average age of the family.
The ratio of the ages of A, B and C, 5 years ago, was 4 : 5 : 7. The sum of their present ages is 135 years. What will be the sum of the ages (in years) of B and C, 3 years from now?
The ratio of the present age of Mahesh and Ajay is 3 : 2 respectively. After 8 years. Ratio of their age will be 11: 8. What will be the present age of Mahesh’s son if his age is half of the present age of Ajay?
In a school, the average age of boys and girls together is 16.8 years, the average age of boys is 15.4 years, and the average age of girls is 18.2 years. The ratio of number of boys to girls in the school is:
The difference between age of Sunita and Sheela is 12 years. If 9 years ago, elder's age was 4 times of younger's age, then what are their present age?
A. 11 and 23
B. 15 and 27
C. 13 and 25
D. 23 and 35