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Question

The ratio of the ages of A, B and C, 5 years ago, was 4 : 5 : 7. The sum of their present ages is 135 years. What will be the sum of the ages (in years) of B and C, 3 years from now?

The correct answer is

106

Understanding and Solving the Ages Ratio Problem

This question involves solving an age problem where the ratio of ages at a past point in time and the sum of present ages are given. We need to find the sum of the ages of two individuals from the group at a future point in time.

Step-by-Step Solution for Age Calculation

Let the ages of A, B, and C, 5 years ago, be represented by a variable \(x\) based on the given ratio. The ratio of their ages 5 years ago was 4 : 5 : 7.

  • Age of A, 5 years ago = \(4x\) years
  • Age of B, 5 years ago = \(5x\) years
  • Age of C, 5 years ago = \(7x\) years

To find their present ages, we add 5 years to their ages 5 years ago:

  • Present age of A = \((4x + 5)\) years
  • Present age of B = \((5x + 5)\) years
  • Present age of C = \((7x + 5)\) years

The sum of their present ages is given as 135 years. We can set up an equation using their present ages:

\((4x + 5) + (5x + 5) + (7x + 5) = 135\)

Now, let's solve this equation to find the value of \(x\):

\(4x + 5x + 7x + 5 + 5 + 5 = 135\)

\(16x + 15 = 135\)

Subtract 15 from both sides:

\(16x = 135 - 15\)

\(16x = 120\)

Divide by 16:

\(x = \frac{120}{16}\)

Simplify the fraction:

\(x = \frac{15 \times 8}{2 \times 8} = \frac{15}{2} = 7.5\)

Now that we have the value of \(x\), we can find the present ages of A, B, and C:

  • Present age of A = \(4x + 5 = 4(7.5) + 5 = 30 + 5 = 35\) years
  • Present age of B = \(5x + 5 = 5(7.5) + 5 = 37.5 + 5 = 42.5\) years
  • Present age of C = \(7x + 5 = 7(7.5) + 5 = 52.5 + 5 = 57.5\) years

Let's verify the sum of present ages:

\(35 + 42.5 + 57.5 = 35 + 100 = 135\) years. This matches the given information.

The question asks for the sum of the ages of B and C, 3 years from now. First, we find their ages 3 years from now:

  • Age of B, 3 years from now = Present age of B + 3 = \(42.5 + 3 = 45.5\) years
  • Age of C, 3 years from now = Present age of C + 3 = \(57.5 + 3 = 60.5\) years

Finally, we find the sum of the ages of B and C, 3 years from now:

Sum of ages of B and C, 3 years from now = Age of B (3 years from now) + Age of C (3 years from now)

Sum = \(45.5 + 60.5 = 106\) years.

Thus, the sum of the ages of B and C, 3 years from now, will be 106 years.

Person Age 5 Years Ago (Ratio) Age 5 Years Ago (\(x\)) Present Age (\(x\)) Age 3 Years From Now
A 4 \(4x\) \(4x+5\) \(4x+8\)
B 5 \(5x\) \(5x+5\) \(5x+8\)
C 7 \(7x\) \(7x+5\) \(7x+8\)

Calculation using \(x\):

  • Sum of B and C's ages 3 years from now = \((5x+8) + (7x+8) = 12x + 16\)
  • Substitute \(x = 7.5\): \(12(7.5) + 16 = 90 + 16 = 106\) years.

Conclusion on Ages Problem

By using the given ratio of ages from the past and the sum of present ages, we were able to determine the value of the variable representing the ratio parts. This allowed us to calculate the present ages and subsequently project the ages 3 years into the future to find the required sum.


Revision Table: Key Concepts in Ages Problems

Concept Explanation Application in this Problem
Ratio of Ages Represents relative ages at a specific time. Use a variable (\(x\)) with the ratio parts. Ages 5 years ago were \(4x, 5x, 7x\).
Present Age Age at the current time. If past age is known, add the number of years passed. If future age is known, subtract the number of years to the future. Present ages are \((4x+5), (5x+5), (7x+5)\).
Future Age Age at a specific time in the future. Add the number of years to the present age. Ages 3 years from now are \((5x+5+3)\) and \((7x+5+3)\).
Sum of Ages The total of the ages of a group of individuals at a specific time. This often forms the basis for an equation. Sum of present ages is 135. Used to find \(x\).

Additional Information: Solving Ratio and Age Questions

Age problems often involve ratios, sums, and differences across different points in time (past, present, future). The key is to establish a consistent variable (like \(x\)) representing the unit of the ratio at a specific time (usually the time point mentioned in the ratio) and then express all other ages relative to that variable and time point.

  • Always be careful with the time reference (e.g., "5 years ago", "3 years from now", "present").
  • When moving from a past age to the present, you add years.
  • When moving from a future age to the present, you subtract years.
  • When comparing two ages, their difference remains constant over time, but their ratio changes.
  • Set up an equation based on the information given about the sum, difference, or relationship between ages at a particular time.
  • Solve the equation for the variable and then substitute it back to find the required ages.

Practicing various types of age problems with different combinations of past, present, and future references and ratios will help build confidence in solving them efficiently.

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Important Questions from Problem on Age

  1. The average age of a husband and his wife was 20 years at the time of their marriage. After 6 years, they have a 2 -year old child. Find the present average age of the family.

  2. The ratio of the present age of Mahesh and Ajay is 3 : 2 respectively. After 8 years. Ratio of their age will be 11: 8. What will be the present age of Mahesh’s son if his age is half of the present age of Ajay?

  3. In a school, the average age of boys and girls together is 16.8 years, the average age of boys is 15.4 years, and the average age of girls is 18.2 years. The ratio of number of boys to girls in the school is:

  4. The difference between age of Sunita and Sheela is 12 years. If 9 years ago, elder's age was 4 times of younger's age, then what are their present age?

    A. 11 and 23

    B. 15 and 27

    C. 13 and 25

    D. 23 and 35

  5. The ratio of alpha and beta to age is 2 ∶ 5. If the sum of their ages is 238, then find the difference between their age.

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