The difference between age of Sunita and Sheela is 12 years. If 9 years ago, elder's age was 4 times of younger's age, then what are their present age? A. 11 and 23 B. 15 and 27 C. 13 and 25 D. 23 and 35
C
The problem asks us to find the present ages of two individuals, Sunita and Sheela, given two conditions about their ages.
Let's break down the information provided:
Let the present age of Sunita be \(S\) years and the present age of Sheela be \(H\) years.
According to the first condition, the difference in their ages is 12 years. This means one is 12 years older than the other. Let's assume Sunita is the elder one for now. So, the first equation is:
\(S - H = 12 \quad (1)\)
From this equation, we can express \(S\) in terms of \(H\):
\(S = H + 12\)
Now, let's consider their ages 9 years ago:
The second condition states that 9 years ago, the elder's age was 4 times the younger's age. Since we assumed Sunita is elder, her age 9 years ago (\(S - 9\)) was 4 times Sheela's age 9 years ago (\(H - 9\)). So, the second equation is:
\(S - 9 = 4 \times (H - 9) \quad (2)\)
We now have a system of two linear equations:
\(S = H + 12\)
\(S - 9 = 4(H - 9)\)
We can substitute the expression for \(S\) from equation (1) into equation (2):
\((H + 12) - 9 = 4(H - 9)\)
Simplify the left side:
\(H + 3 = 4(H - 9)\)
Distribute the 4 on the right side:
\(H + 3 = 4H - 36\)
Now, we need to isolate \(H\). Subtract \(H\) from both sides:
\(3 = 4H - H - 36\)
\(3 = 3H - 36\)
Add 36 to both sides:
\(3 + 36 = 3H\)
\(39 = 3H\)
Divide by 3 to find \(H\):
\(H = \frac{39}{3}\)
\(H = 13\)
So, Sheela's present age is 13 years.
Now substitute the value of \(H\) back into the equation \(S = H + 12\) to find Sunita's present age:
\(S = 13 + 12\)
\(S = 25\)
So, Sunita's present age is 25 years.
The present ages are 25 years and 13 years. Since we assumed Sunita was elder (\(S > H\)), and we got \(25 > 13\), our assumption was consistent.
Let's check if these ages satisfy both original conditions:
Both conditions are met, so the present ages are 25 years and 13 years.
The calculated present ages are 13 years and 25 years. Looking at the options:
Option C provides the ages 13 and 25, which is consistent with our solution.
| Age Category | Sunita (Elder) | Sheela (Younger) |
|---|---|---|
| Present Age | 25 years | 13 years |
| Age 9 Years Ago | \(25 - 9 = 16\) years | \(13 - 9 = 4\) years |
Based on the given conditions and our calculations, the present ages of Sunita and Sheela are 25 years and 13 years.
| Concept | Explanation | Example Handling |
|---|---|---|
| Representing Ages | Use variables (e.g., x, y) for unknown ages. | Let present age = x. Age after 5 years = x+5. Age 3 years ago = x-3. |
| Age Difference | The difference remains constant over time. | If difference is D now, it was D years ago, and will be D years from now. |
| Forming Equations | Translate word problem statements into mathematical equations based on age relationships (sum, difference, ratio). | "Sum of ages is 30": \(x+y = 30\). "One age is twice the other": \(x=2y\). |
| Solving Equations | Use substitution or elimination methods to solve the system of equations. | Solve for one variable in terms of the other, then substitute into the second equation. |
| Verification | Plug the calculated ages back into the original statements to check if they satisfy all conditions. | Ensure the ages fit the difference AND the relationship at the past/future time. |
Age problems are common in mathematics and often appear in competitive exams. They typically involve finding the present age of one or more people based on conditions about their ages at different points in time (past, present, or future). Here are some tips for solving age problems:
Understanding how to set up and solve linear equations is fundamental to solving age problems effectively.
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