Three of the following four number-pairs are alike in a certain way and one is different. Pickthe odd pair out.
49 : 218
This question presents four pairs of numbers, and we need to find the one pair that is different from the other three. This usually means there is a pattern or rule that applies to three of the pairs, but not to the fourth one.
To solve this, we need to examine the relationship between the two numbers in each pair and try to find a consistent rule.
Let's list the four number pairs:
We can often find patterns involving basic mathematical operations, powers, or relationships between the numbers.
Let's look at the numbers themselves. Many are perfect squares or perfect cubes:
Let's try to find a relationship between the first and second number in each pair using these powers.
| Pair | First Number | Second Number | Observation |
|---|---|---|---|
| 4 : 27 | 4 $= 2^2$ |
27 $= 3^3$ |
The base of the cube (3) is one more than the base of the square (2). This suggests a pattern like $n^2 : (n+1)^3$. Here $n=2$. |
| 16 : 125 | 16 $= 4^2$ |
125 $= 5^3$ |
The base of the cube (5) is one more than the base of the square (4). This fits the pattern $n^2 : (n+1)^3$. Here $n=4$. |
| 9 : 64 | 9 $= 3^2$ |
64 $= 4^3$ |
The base of the cube (4) is one more than the base of the square (3). This fits the pattern $n^2 : (n+1)^3$. Here $n=3$. Note that 64 is also $8^2$, but $3^2 : 8^2$ doesn't fit the $(n+1)$ relationship seen in the first two pairs. |
| 49 : 218 | 49 $= 7^2$ |
218 |
The first number is $7^2$. If the pattern $n^2 : (n+1)^3$ holds, the second number should be $(7+1)^3 = 8^3$. |
Let's calculate $8^3$ for the fourth pair:
$8^3 = 8 \times 8 \times 8 = 64 \times 8 = 512$.
So, if the fourth pair followed the same pattern $n^2 : (n+1)^3$ with $n=7$, it should be 49 : 512. However, the given pair is 49 : 218.
Therefore, the first three pairs follow the pattern $n^2 : (n+1)^3$, while the fourth pair does not.
Based on our analysis, the pair 49 : 218 is the one that is different from the other three, as it does not fit the $n^2 : (n+1)^3$ pattern.
Thus, the odd pair out is 49 : 218.
| Pair | First Number Form ($n^2$) | Second Number Form ($(n+1)^3$) | Expected Second Number | Actual Second Number | Fits Pattern? |
|---|---|---|---|---|---|
| 4 : 27 | $2^2$ | $(2+1)^3 = 3^3$ | 27 | 27 | Yes |
| 16 : 125 | $4^2$ | $(4+1)^3 = 5^3$ | 125 | 125 | Yes |
| 9 : 64 | $3^2$ | $(3+1)^3 = 4^3$ | 64 | 64 | Yes |
| 49 : 218 | $7^2$ | $(7+1)^3 = 8^3$ | 512 | 218 | No |
Odd pair out questions involving numbers test your ability to find logical rules or patterns. These can be based on various mathematical concepts:
To improve at these questions, practice recognizing common sequences and properties of numbers quickly.
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