The value of \(\frac{tan^2 30^\circ+sin^290^\circ+cot^260^\circ+sin^230^\circ cos^245^\circ}{sin60^\circ cos30^\circ-cos60^\circ sin30^\circ}\)
43/12
The question asks us to find the value of a given trigonometric expression:
\[ \frac{\tan^2 30^\circ + \sin^2 90^\circ + \cot^2 60^\circ + \sin^2 30^\circ \cos^2 45^\circ}{\sin 60^\circ \cos 30^\circ - \cos 60^\circ \sin 30^\circ} \]
To evaluate this expression, we need to know the values of the trigonometric functions for the standard angles \(30^\circ, 45^\circ, 60^\circ,\) and \(90^\circ\).
Here are the standard values we will use:
| Angle | \(\sin \theta\) | \(\cos \theta\) | \(\tan \theta\) | \(\cot \theta\) |
|---|---|---|---|---|
| \(30^\circ\) | \(\frac{1}{2}\) | \(\frac{\sqrt{3}}{2}\) | \(\frac{1}{\sqrt{3}}\) | \(\sqrt{3}\) |
| \(45^\circ\) | \(\frac{1}{\sqrt{2}}\) | \(\frac{1}{\sqrt{2}}\) | \(1\) | \(1\) |
| \(60^\circ\) | \(\frac{\sqrt{3}}{2}\) | \(\frac{1}{2}\) | \(\sqrt{3}\) | \(\frac{1}{\sqrt{3}}\) |
| \(90^\circ\) | \(1\) | \(0\) | Undefined | \(0\) |
The numerator is \(\tan^2 30^\circ + \sin^2 90^\circ + \cot^2 60^\circ + \sin^2 30^\circ \cos^2 45^\circ\).
Substitute the standard values:
Now, add these values together for the numerator:
\[ \text{Numerator} = \frac{1}{3} + 1 + \frac{1}{3} + \frac{1}{8} \]
Combine the fractions with like denominators:
\[ \text{Numerator} = \left(\frac{1}{3} + \frac{1}{3}\right) + 1 + \frac{1}{8} = \frac{2}{3} + 1 + \frac{1}{8} \]
To add these, find a common denominator, which is 24:
\[ \text{Numerator} = \frac{2 \times 8}{3 \times 8} + \frac{1 \times 24}{1 \times 24} + \frac{1 \times 3}{8 \times 3} = \frac{16}{24} + \frac{24}{24} + \frac{3}{24} \]
\[ \text{Numerator} = \frac{16 + 24 + 3}{24} = \frac{43}{24} \]
The denominator is \(\sin 60^\circ \cos 30^\circ - \cos 60^\circ \sin 30^\circ\).
Substitute the standard values:
So, the denominator is:
\[ \text{Denominator} = \left(\frac{\sqrt{3}}{2}\right) \left(\frac{\sqrt{3}}{2}\right) - \left(\frac{1}{2}\right) \left(\frac{1}{2}\right) \]
\[ \text{Denominator} = \frac{\sqrt{3} \times \sqrt{3}}{2 \times 2} - \frac{1 \times 1}{2 \times 2} = \frac{3}{4} - \frac{1}{4} \]
\[ \text{Denominator} = \frac{3 - 1}{4} = \frac{2}{4} = \frac{1}{2} \]
Alternatively, we can recognise the trigonometric identity \(\sin(A - B) = \sin A \cos B - \cos A \sin B\). The denominator has the form \(\sin 60^\circ \cos 30^\circ - \cos 60^\circ \sin 30^\circ\), which is \(\sin(60^\circ - 30^\circ) = \sin 30^\circ\). The value of \(\sin 30^\circ\) is \(\frac{1}{2}\). Both methods give the same result for the denominator.
The expression is \(\frac{\text{Numerator}}{\text{Denominator}}\).
Substitute the calculated values:
\[ \text{Value} = \frac{\frac{43}{24}}{\frac{1}{2}} \]
To divide by a fraction, multiply by its reciprocal:
\[ \text{Value} = \frac{43}{24} \times \frac{2}{1} = \frac{43 \times 2}{24 \times 1} = \frac{86}{24} \]
Simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 2:
\[ \text{Value} = \frac{86 \div 2}{24 \div 2} = \frac{43}{12} \]
Thus, the value of the given trigonometric expression is \(\frac{43}{12}\).
| Function | \(30^\circ\) | \(45^\circ\) | \(60^\circ\) | \(90^\circ\) |
|---|---|---|---|---|
| \(\sin\) | \(\frac{1}{2}\) | \(\frac{1}{\sqrt{2}}\) | \(\frac{\sqrt{3}}{2}\) | \(1\) |
| \(\cos\) | \(\frac{\sqrt{3}}{2}\) | \(\frac{1}{\sqrt{2}}\) | \(\frac{1}{2}\) | \(0\) |
| \(\tan\) | \(\frac{1}{\sqrt{3}}\) | \(1\) | \(\sqrt{3}\) | Undefined |
| \(\cot\) | \(\sqrt{3}\) | \(1\) | \(\frac{1}{\sqrt{3}}\) | \(0\) |
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