What is the value of \(\cos \left(\frac{5 \pi}{17}\right)+\cos \left(\frac{7 \pi}{17}\right)+2 \cos \left(\frac{11 \pi}{17}\right) \cos \left(\frac{\pi}{17}\right)\) ?
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The problem asks us to find the value of the expression: \[ \cos \left(\frac{5 \pi}{17}\right)+\cos \left(\frac{7 \pi}{17}\right)+2 \cos \left(\frac{11 \pi}{17}\right) \cos \left(\frac{\pi}{17}\right) \] To solve this, we can use trigonometric identities to simplify the terms.
Let's first simplify the last term, which is in the form of a product of two cosine functions: \(2 \cos A \cos B\). We use the product-to-sum identity: \[ 2 \cos A \cos B = \cos(A+B) + \cos(A-B) \] Here, let \(A = \frac{11 \pi}{17}\) and \(B = \frac{\pi}{17}\).
Calculating the sum and difference of the angles:
So, applying the identity:
\[ 2 \cos \left(\frac{11 \pi}{17}\right) \cos \left(\frac{\pi}{17}\right) = \cos \left(\frac{12 \pi}{17}\right) + \cos \left(\frac{10 \pi}{17}\right) \]Now, substitute this result back into the original expression:
\[ \cos \left(\frac{5 \pi}{17}\right)+\cos \left(\frac{7 \pi}{17}\right)+\left(\cos \left(\frac{12 \pi}{17}\right) + \cos \left(\frac{10 \pi}{17}\right)\right) \]Rearrange the terms for easier grouping:
\[ \cos \left(\frac{5 \pi}{17}\right) + \cos \left(\frac{12 \pi}{17}\right) + \cos \left(\frac{7 \pi}{17}\right) + \cos \left(\frac{10 \pi}{17}\right) \]Observe the angles in the expression. Notice that some angles are supplementary (sum up to \(\pi\)). We can use the property \(\cos(\pi - x) = -\cos x\).
The original expression simplifies to the sum of the values of these two pairs:
\[ 0 + 0 = 0 \]Thus, the value of the given trigonometric expression is 0.
| Term | Identity/Property Used | Simplification |
|---|---|---|
| \(2 \cos \left(\frac{11 \pi}{17}\right) \cos \left(\frac{\pi}{17}\right)\) | \(2 \cos A \cos B = \cos(A+B) + \cos(A-B)\) | \(\cos \left(\frac{12 \pi}{17}\right) + \cos \left(\frac{10 \pi}{17}\right)\) |
| \(\cos \left(\frac{5 \pi}{17}\right) + \cos \left(\frac{12 \pi}{17}\right)\) | \(\cos(\pi - x) = -\cos x\) | \(\cos \left(\frac{5 \pi}{17}\right) - \cos \left(\frac{5 \pi}{17}\right) = 0\) |
| \(\cos \left(\frac{7 \pi}{17}\right) + \cos \left(\frac{10 \pi}{17}\right)\) | \(\cos(\pi - x) = -\cos x\) | \(\cos \left(\frac{7 \pi}{17}\right) - \cos \left(\frac{7 \pi}{17}\right) = 0\) |
| Entire Expression | Summing simplified terms | \(0 + 0 = 0\) |
By applying the product-to-sum identity and recognizing the relationship between angles summing to \(\pi\), we simplified the expression to find its value.
| Identity Type | Formula |
|---|---|
| Product-to-Sum | \(2 \cos A \cos B = \cos(A+B) + \cos(A-B)\) |
| Angle Relationship | \(\cos(\pi - x) = -\cos x\) |
| Angle Value | \(\cos(\pi/2) = 0\) |
Angles in trigonometric functions are often expressed in radians. A full circle is \(2\pi\) radians, which is equivalent to 360 degrees. Half a circle is \(\pi\) radians, equivalent to 180 degrees. When working with angles like \(\frac{5\pi}{17}\), we are dealing with fractions of \(\pi\), representing a specific position on the unit circle. Understanding these relationships helps in simplifying trigonometric expressions and using identities like \(\cos(\pi - x) = -\cos x\).
The property \(\cos(\pi - x) = -\cos x\) arises because if an angle is \(x\), the angle \(\pi - x\) is its supplement. On the unit circle, these angles are symmetric with respect to the y-axis, resulting in cosine values that are equal in magnitude but opposite in sign.
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