The value of \(\sqrt {28 + 10\sqrt 3 } - \sqrt {7 - 4\sqrt 3 }\) is closest to:
6.5
Express each radicand as a perfect square. For \(28+10\sqrt{3}\), try \((a+b\sqrt{3})^2=a^2+3b^2+2ab\sqrt{3}\): matching gives \(ab=5,\;a^2+3b^2=28\Rightarrow a=5,b=1\). So \(\sqrt{28+10\sqrt{3}}=5+\sqrt{3}\).
For \(7-4\sqrt{3}\): \(cd=2,\;c^2+3d^2=7\Rightarrow c=2,d=1\), giving \(\sqrt{7-4\sqrt{3}}=2-\sqrt{3}\).
Difference: \((5+\sqrt{3})-(2-\sqrt{3})=3+2\sqrt{3}\approx 3+3.464=6.464\), closest to 6.5.
If \(\frac{\sqrt{38-5\sqrt{3} } }{\sqrt{26+7\sqrt{3} } }= \frac{a+b\sqrt{3} }{23} \) , b > 0, then the value of (b – a) is:
If \(\frac {8 + 2\sqrt 3}{3\sqrt 3 + 5} = a\sqrt 3 - b,\) then the value of a + b is equal to:
If \(\frac{\sqrt{26-7\sqrt{3} } }{\sqrt{14+5\sqrt{3} } } = \frac{b+a\sqrt{3} }{11}\) , b > 0, then what is the value of \(\sqrt{(b-a)} \) ?
If \(\frac{{22\sqrt 2 }}{{4\sqrt 2 - \sqrt {3\, + \,\sqrt 5 }}}\) = \(a + \sqrt 5 b\) , with a, b > 0, then what is the value of (ab) ∶ (a + b)?
The value of \(\frac{1}{{4 - \sqrt {15} }} - \frac{1}{{\sqrt {15} - \sqrt {14} }} + \frac{1}{{\sqrt {14} - \sqrt {13} }} - \frac{1}{{\sqrt {13} - \sqrt {12} }} + \frac{1}{{\sqrt {12} - \sqrt {11} }} - \frac{1}{{\sqrt {11} - \sqrt {10} }} + \frac{1}{{\sqrt {10} - 3}} - \frac{1}{{3 - \sqrt 8 }}\) is:
If x = \(\sqrt {1 + \frac{{\sqrt 3 }}{2}} - \sqrt {1 - \frac{{{\kern 1pt} \sqrt 3 }}{2}} \) , then the value of \(\frac{{\sqrt 3 - x}}{{\sqrt 3 + x}}\) (corrected to two decimal places) is:
Sum of four times a fraction and 7 times its reciprocal is 16. What is the fraction?
Let \(x\; = \;\sqrt[6]{{27}} - \sqrt {6\frac{3}{4}}\) and \(\;y\; = \;\frac{{\sqrt {45\;} \; + \;\sqrt {605} \; + \;\sqrt {245} }}{{\sqrt {80\;} \; + \;\sqrt {125} }}\) , then the value of x 2+ y 2is :
The value of \(\frac{{2\sqrt {10} }}{{\sqrt 5 \; + \;\sqrt 2 - \sqrt 7 }} - \sqrt {\frac{{\sqrt 5 - 2}}{{\sqrt 5 \; + \;2}}} - \frac{3}{{\sqrt 7 - 2}}\;\) is:
Which of the following is TRUE?
\({\rm{I}}.{\rm{\;}}\frac{1}{{\sqrt[3]{{12}}}} > \frac{1}{{\sqrt[4]{{29}}}} > \frac{1}{{\sqrt 5 }}\)
\({\rm{II}}.\;\frac{1}{{\sqrt[4]{{29}}}} > \frac{1}{{\sqrt[3]{{12}}}} > \frac{1}{{\sqrt 5 }}\)
\({\rm{III}}.\;\frac{1}{{\sqrt 5 }} > \frac{1}{{\sqrt[3]{{12}}}} > \frac{1}{{\sqrt[4]{{29}}}}\)
\({\rm{IV}}.{\rm{\;}}\frac{1}{{\sqrt 5 }} > \frac{1}{{\sqrt[4]{{29}}}} > \frac{1}{{\sqrt[3]{{12}}}}\)
Which of the following number is irrational?
Which of the following numbers will have an irrational square root?
What is the square root of 16 + 6√7?
A non-terminating but recurring decimal is:
Which of the following is false?