The turnover frequency (in $h^{-1}$) of a reaction where 5 mol% of a catalyst is required for 90% conversion in 3 h is ________.
(rounded off to the nearest integer)
Understanding Turnover Frequency (TOF)
Turnover Frequency (TOF) measures the catalytic activity, specifically the number of substrate molecules converted per active site (or per mole of catalyst) per unit time.
The formula for TOF is:
$TOF = (Moles of substrate converted) / (Moles of catalyst × Time)$
Calculating TOF for the Reaction
We need to determine the moles converted and the moles of catalyst used.
- Assume a basis: Let's assume we start with 100 moles of the reactant substrate.
- Calculate moles converted: The reaction achieves 90% conversion. Moles converted = 90% of 100 mol = $0.90 \times 100 \text{ mol} = 90 \text{ mol}$
- Calculate moles of catalyst: The catalyst loading is 5 mol%. Moles of catalyst = 5% of 100 mol (basis substrate) = $0.05 \times 100 \text{ mol} = 5 \text{ mol}$
- Calculate TOF: The reaction time is 3 hours.
$TOF = (90 \text{ mol}) / (5 \text{ mol} \times 3 \text{ h})$
$TOF = 90 / 15 \text{ h}^{-1}$
$TOF = 6 \text{ h}^{-1}$
- Rounding: The question asks for the value rounded to the nearest integer. The calculated TOF is exactly 6.
Therefore, the turnover frequency is 6 $h^{-1}$.
Important Questions from Catalysis
The rate-determining step in the catalytic synthesis of acetic acid by Monsanto process is
The homogeneous catalyst whose metal ion does NOT undergo either oxidation or reduction in any of the steps during the hydrogenation of terminal olefins is
The elimination product of the following reaction is
In Monsanto acetic acid process shown below, the role of HI is
$CH_3OH + CO \frac{{\text{Rh(I) catalyst / HI}}}{180 °C, 30 bar} CH_3CO_2H$
- The interconversion of oxidation states of metal(s) observed in Wacker process is(are)
