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Question

The elimination product of the following reaction is

The correct answer is
$CH_3COI$

This question involves the analysis of a reaction mechanism to determine the elimination product. Let's break down the problem step-by-step:

  1. **Identify the Reaction Conditions and Reagents:**
    • The reaction given involves carbon monoxide (CO) at 35 bar and a temperature of 453 K.
    • The starting complex is a Rhodium complex with iodide (I) and carbonyl (CO) ligands.
  2. **Understand the Likely Reaction Mechanism:**
    • The given conditions suggest a process involving CO insertion or ligand substitution/elimination.
    • Rhodium complexes often participate in reactions, such as oxidative addition, reductive elimination, or migratory insertion.
  3. **Analyze the Potential Products:**
    • The elimination process here likely involves replacing or eliminating a ligand from the Rhodium complex.
    • Among the options given:
      • \(I_2\): Unlikely, as iodine is bonded directly to Rh.
      • \(CH_3I\): There is no direct CH3 group that would form this product.
      • \(CH_3COI\): Involves the elimination of a single CH3CO group, likely forming by substitution or migration.
      • \(I_3^−\): Involves three iodine atoms, which doesn't fit the elimination context here.
  4. **Conclusion:**
    • The most plausible elimination product, considering the CO and reaction conditions, is \(CH_3COI\), where the carbonyl group eliminates as an acyl iodide.

Therefore, the correct answer is \(CH_3COI\).

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Important Questions from Catalysis

  1. The rate-determining step in the catalytic synthesis of acetic acid by Monsanto process is

  2. The homogeneous catalyst whose metal ion does NOT undergo either oxidation or reduction in any of the steps during the hydrogenation of terminal olefins is

  3. The turnover frequency (in $h^{-1}$) of a reaction where 5 mol% of a catalyst is required for 90% conversion in 3 h is ________. 
    (rounded off to the nearest integer)

  4. In Monsanto acetic acid process shown below, the role of HI is

    $CH_3OH + CO  \frac{{\text{Rh(I) catalyst / HI}}}{180 °C, 30 bar}  CH_3CO_2H$

  5. The interconversion of oxidation states of metal(s) observed in Wacker process is(are)
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