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Question

The taxi charges in a city consist of a fixed charge together with the charge per kilometre for the distance covered. For a distance of 35 km, the charge paid is ₹375 and for a distance of 48 km, the charge paid is ₹427. Find the fixed charges and the charge per km (in ₹), respectively.

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is

235 and 4

To solve the problem of finding the fixed charges and charge per kilometer for a taxi service, consider the following:

  • Let the fixed charge be denoted as F (in ₹).
  • Let the charge per kilometer be k (in ₹).
    The charges for a given trip can be represented by the equation:

Charge = F + (Distance × k)

We are given two scenarios:

  1. For a distance of 35 km, the total charge is ₹375:
    375 = F + 35k
  2. For a distance of 48 km, the total charge is ₹427:
    427 = F + 48k

We now have two equations:

  1. F + 35k = 375
  2. F + 48k = 427

We can solve these equations simultaneously to find the values of F and k:

Subtract equation (1) from equation (2):
(F + 48k) - (F + 35k) = 427 - 375
48k - 35k = 52
13k = 52
k = 52/13 => k = 4

Now, substitute the value of k back into equation (1):
F + 35(4) = 375
F + 140 = 375
F = 375 - 140
F = 235

Thus, the fixed charge is ₹235 and the charge per kilometer is ₹4.

The correct answer is: 235 and 4.

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