Given the system of two linear equations:
The objective is to determine the specific numerical values for x and y that satisfy both equations simultaneously.
\(x + 50 \left( \frac{1}{10}x \right) = 120\)
Combine terms involving \(x\): \(x + \frac{50}{10}x = 120\) \(x + 5x = 120\) \(6x = 120\)
Isolate \(x\) by dividing both sides by 6: \(x = \frac{120}{6}\) \(x = 20\)
Substitute the value \(x = 20\) back into Equation 1: \(y = \frac{1}{10}(20)\) \(y = \frac{20}{10}\) \(y = 2\)
Thus, the solution to the system of equations is x = 20 and y = 2.
The taxi charges in a city consist of a fixed charge together with the charge per kilometre for the distance covered. For a distance of 35 km, the charge paid is ₹375 and for a distance of 48 km, the charge paid is ₹427. Find the fixed charges and the charge per km (in ₹), respectively.
The cost of 6 pens and 19 pencils is ₹275. If the cost of a pen decreases by ₹7 and the cost of a pencil increases by ₹7, then the cost of 15 pens and 4 pencils is 132. What is the original cost of 6 pens and 2 pencils?