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Question

The following lines with the equations
$x + 2y = 12$,
$4x + 8y = 48$

This question was previously asked in
RRB ALP/Technician 2018 CBT 2 Electronics Mechanic Question Paper (23-Jan-2019) (Shift 1)
The correct answer is
are coincident with each other

To determine the relationship between the given lines, we need to analyze their equations:

  1. The first equation is given as \(x + 2y = 12\).
  2. The second equation is \(4x + 8y = 48\).

Let's simplify both equations and compare them:

  1. For the first equation \(x + 2y = 12\), it is already in simplified form.
  2. Simplifying the second equation \(4x + 8y = 48\) by dividing every term by 4:
    • \(\dfrac{4x}{4} + \dfrac{8y}{4} = \dfrac{48}{4}\)
    • This simplifies to \(x + 2y = 12\).

We see that both equations simplify to the same equation \(x + 2y = 12\). Thus, the two lines are coincident, which means they lie on top of each other and have infinitely many solutions.

Now, let's rule out the other options:

  • Are perpendicular to each other: Two lines are perpendicular if the product of their slopes is \(-1\). Here, both lines have the same slope, so this option is incorrect.
  • Are parallel: Two lines are parallel if they have the same slope but different intercepts. Since these lines have the same equation, this option is incorrect.
  • Pass through the origin: A line passes through the origin if its equation can be expressed in the form \(ax + by = 0\). Here, the lines do not pass through the origin as they intersect the axes at different points not linked to the origin.

Therefore, the correct answer is that the lines are coincident with each other.

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Similar Questions

  1. Let \(y = \frac{1}{10}x\) and \(x + 50y = 120\). What is the value of x and y?
  2. Solutions for the following pair of equations would be
    $x + 2y = 6$,
    $x - 2y = 16$
  3. If \(2x-y=7\) and \(x-y=6\), then value of x and y will be
  4. The taxi charges in a city consist of a fixed charge together with the charge per kilometre for the distance covered. For a distance of 35 km, the charge paid is ₹375 and for a distance of 48 km, the charge paid is ₹427. Find the fixed charges and the charge per km (in ₹), respectively.


Important Questions from Linear Equation in 2 Variable

  1. The cost of 6 pens and 19 pencils is ₹275. If the cost of a pen decreases by ₹7 and the cost of a pencil increases by ₹7, then the cost of 15 pens and 4 pencils is 132. What is the original cost of 6 pens and 2 pencils?

  2. The cost of 12 pens and 7 pencils is ₹285. If the cost of a pen decreases by ₹6 and the cost of a pencil increases by ₹5, then the cost of 11 pens and 3 pencils is ₹118. What is the original cost of 2 pens and 2 pencils?
  3. The cost of 7 pens and 17 pencils is ₹92. If the cost of a pen decreases by ₹0.50 and the cost of a pencil increases by ₹8, then the cost of 8 pens and 14 pencils is 186. What is the original cost of 9 pens and 6 pencils?
  4. The cost of 19 pens and 13 pencils is ₹254. If the cost of a pen decreases by ₹6 and the cost of a pencil increases by ₹9, then the cost of 14 pens and 2 pencils is ₹106. What is the original cost of 12 pens and 15 pencils?
  5. The price of 4 pens and 5 notebooks is ₹130. If the price of a pen increases by 25% and the price of a notebook decreases by 20%, then the price of 2 pens and 4 notebooks becomes ₹82. What is the original price of 1 pen and 2 notebooks?
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