The problem involves finding the number of diagonals in a regular polygon based on the relationship between the sum of its interior angles and the sum of its exterior angles.
We use the standard formulas for the sum of interior and exterior angles of a polygon with n sides:
The problem states that the sum of the interior angles is six times the sum of the exterior angles:
$\(n-2) \times 180^\circ = 6 \times 360^\circ$
To find n, we solve this equation:
The polygon has 14 sides.
The formula for the number of diagonals in a polygon with n sides is:
Number of diagonals = $\\frac{n(n-3)}{2}$
Substitute the value $\n=14$ into the formula:
Number of diagonals = $\\frac{14(14-3)}{2}$
Number of diagonals = $\\frac{14 \times 11}{2}$
Number of diagonals = $\\frac{154}{2}$
Number of diagonals = $\77$
Therefore, the polygon has 77 diagonals.
ABCDEF is a regular hexagon. Side of the hexagon is 36 cm. What is the area of the triangle AOB ?
If ∆ABC ~ ∆DEF, and BC = 4 cm, EF = 5 cm and the area of triangle ABC = 80 cm 2, then the area of the triangle DEF is:
If Δ ABC is right angled at B, AB = 12 cm and ∠CAB = 60°, determine the length of BC.
If ΔABC and ΔDEF are congruent triangles, then which of the following is FALSE?
D and E are points on the sides AB and AC, respectively, of ΔABC such that DE is parallel to BC and AD ∶ DB = 7 ∶ 9. If CD and BE intersect each other at F. then find the ratio of areas of ΔDEF and ΔCBF.