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Question

The sum of the interior angles of a regular polygon is six times the sum of its exterior angles. Determine the number of diagonals in the polygon.

This question was previously asked in
SSC CGL 2025 Tier 1 Question Paper (25-Sep-2025) (Shift 3)
The correct answer is
77

Polygon Diagonals from Angle Sums

The problem involves finding the number of diagonals in a regular polygon based on the relationship between the sum of its interior angles and the sum of its exterior angles.

Finding the Number of Sides (n)

We use the standard formulas for the sum of interior and exterior angles of a polygon with n sides:

  • Sum of interior angles = $\(n-2) \times 180^\circ$
  • Sum of exterior angles = $\360^\circ$

The problem states that the sum of the interior angles is six times the sum of the exterior angles:

$\(n-2) \times 180^\circ = 6 \times 360^\circ$

To find n, we solve this equation:

  1. Divide both sides by $\180^\circ$: $\n-2 = 6 \times \frac{360^\circ}{180^\circ}$ $\n-2 = 6 \times 2$ $\n-2 = 12$
  2. Add 2 to both sides: $\n = 12 + 2$ $\n = 14$

The polygon has 14 sides.

Calculating the Number of Diagonals

The formula for the number of diagonals in a polygon with n sides is:

Number of diagonals = $\\frac{n(n-3)}{2}$

Substitute the value $\n=14$ into the formula:

Number of diagonals = $\\frac{14(14-3)}{2}$

Number of diagonals = $\\frac{14 \times 11}{2}$

Number of diagonals = $\\frac{154}{2}$

Number of diagonals = $\77$

Therefore, the polygon has 77 diagonals.

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Important Questions from Geometry

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