The question relates the angle subtended by a chord at the center of a circle to the angle subtended by the same chord at a point on the circumference. We use a fundamental theorem of circles for this.
We are given the angle subtended by chord AB at the center.
Using the theorem:
Angle at Center = $2 \times \angle ACB$
$80^\circ = 2 \times \angle ACB$
To find $\angle ACB$, we rearrange the equation:
$\angle ACB = \frac{80^\circ}{2}$
$\angle ACB = 40^\circ$
Therefore, the measure of angle $\angle ACB$ is $40^\circ$. This corresponds to Option A.
ABCDEF is a regular hexagon. Side of the hexagon is 36 cm. What is the area of the triangle AOB ?
If ∆ABC ~ ∆DEF, and BC = 4 cm, EF = 5 cm and the area of triangle ABC = 80 cm 2, then the area of the triangle DEF is:
If Δ ABC is right angled at B, AB = 12 cm and ∠CAB = 60°, determine the length of BC.
If ΔABC and ΔDEF are congruent triangles, then which of the following is FALSE?
D and E are points on the sides AB and AC, respectively, of ΔABC such that DE is parallel to BC and AD ∶ DB = 7 ∶ 9. If CD and BE intersect each other at F. then find the ratio of areas of ΔDEF and ΔCBF.