The radius of a circle inscribed within a triangle (also known as the inradius) can be determined using the triangle's area and side lengths. The key formula connecting these elements is:
$ A = rs $
The semi-perimeter ($s$) is half the sum of the lengths of the triangle's sides ($a$, $b$, $c$).
$ s = \frac{a+b+c}{2} $
Substitute the expression for the semi-perimeter ($s$) into the area formula ($A = rs$):
$ A = r \left( \frac{a+b+c}{2} \right) $
To find the radius ($r$), rearrange the equation:
$ r = \frac{A}{\left( \frac{a+b+c}{2} \right)} $
Simplify the expression:
$ r = \frac{2A}{a+b+c} $
Therefore, the radius of the inscribed circle in triangle ABC is given by the formula $\frac{2A}{a+b+c}$. This matches Option B.
The sides of a triangle are in the ratio 6 : 4 : 3 and its perimeter is 104 cm. The length of the longest side (in cm) is:
An isosceles right-angled triangle has hypotenuse length as 10 units. What is the area of the triangle (in square units)?
Two circles of radii 16 cm and 4 cm, respectively, touch each other externally at Point A. PQ is the direct common tangent of these circles with centres C1 and C2, respectively. What is the length of PQ?
Let C be a circle with center O and AB be a chord of C such that the length of AB is equal to the radius of C. Let D be any point on the major arc of AB. Find ∠AOB and ∠ADB, respectively.
The centres of two circles are 84 cm apart. If the radii of these two circles are 38 cm and 26 cm, respectively, then which of the following options gives the length (in cm) of a direct common tangent of these two circles?