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Question

A triangle ABC has a circle inscribed within it with sides a, b, c. The area of the triangle is A. What is the radius of the inscribed circle?

This question was previously asked in
SSC CGL 2025 Tier 1 Question Paper (25-Sep-2025) (Shift 3)
The correct answer is
$\frac{2A}{a+b+c}$

Triangle Inscribed Circle Radius Formula

The radius of a circle inscribed within a triangle (also known as the inradius) can be determined using the triangle's area and side lengths. The key formula connecting these elements is:

$ A = rs $

  • A represents the area of the triangle.
  • r represents the radius of the inscribed circle (inradius).
  • s represents the semi-perimeter of the triangle.

Calculating the Semi-perimeter

The semi-perimeter ($s$) is half the sum of the lengths of the triangle's sides ($a$, $b$, $c$).

$ s = \frac{a+b+c}{2} $

Deriving the Inradius Formula

Substitute the expression for the semi-perimeter ($s$) into the area formula ($A = rs$):

$ A = r \left( \frac{a+b+c}{2} \right) $

To find the radius ($r$), rearrange the equation:

$ r = \frac{A}{\left( \frac{a+b+c}{2} \right)} $

Simplify the expression:

$ r = \frac{2A}{a+b+c} $

Conclusion

Therefore, the radius of the inscribed circle in triangle ABC is given by the formula $\frac{2A}{a+b+c}$. This matches Option B.

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