To find the sum of the interior angles of a polygon, we use a specific formula based on the number of sides.
The formula for the sum of the interior angles of a polygon with n sides is:
$ \text{Sum} = (n-2) \times 180^\circ $
In this question, the polygon has 11 sides. So, we set n = 11.
$ \text{Sum} = (11-2) \times 180^\circ $
$ \text{Sum} = 9 \times 180^\circ $
$ \text{Sum} = 1620^\circ $
The sum of the interior angles of a polygon with 11 sides is $1620^\circ$. This matches Option 4.
The sum of all interior angles of a regular polygon is 1800°. How many diagonals does the polygon have?
The difference between the measure of an interior angle and an exterior angle of a regular polygon is 100°. What is the number of sides of the polygon?
If the area of a square is 625 cm 2, then what is the perimeter of the square?
The area and the perimeter of a sheet of paper are 240 cm 2and 68 cm, respectively. What would be its length and breadth?
One side of rectangular field is 15 meters and one of its diagonals is 17 meters. Then find the area of the field.
The bisector of ∠B in ΔABC meets AC at D. If AB = 12 cm, BC = 18 cm and AC = 15 cm, then the length of AD (in cm) is:
The perimeter and the length of one of the diagonals of a rhombus is 26 cm and 5 cm respectively. Find the length of its other diagonal (in cm).