All Exams Test series for 1 year @ ₹349 only
Question

The standard deviation of the first 10 natural numbers is 3.028. What will be the standard deviation of the first 20 natural numbers?

This question was previously asked in
SSC CGL 2022 Tier-II (Paper 2 JSO) Previous Year Paper (04-Mar-2023)
The correct answer is

5.845

Calculating Standard Deviation of First 20 Natural Numbers

Understanding the standard deviation of a set of numbers helps us measure how spread out the numbers are from their average. For the set of the first n natural numbers, which are $1, 2, 3, \dots, n$, there is a specific formula to calculate the population standard deviation ($\sigma$).

Formula for Standard Deviation

The population standard deviation ($\sigma$) of the first n natural numbers is given by the formula:

\(\sigma = \sqrt{\frac{n^2 - 1}{12}}\)

Calculating Standard Deviation for the First 20 Natural Numbers

We need to find the standard deviation for the first 20 natural numbers. Here, n = 20.

Let's substitute n = 20 into the formula:

\(\sigma_{20} = \sqrt{\frac{20^2 - 1}{12}}\)

First, calculate \(20^2\):

\(20^2 = 400\)

Now substitute this back into the formula:

\(\sigma_{20} = \sqrt{\frac{400 - 1}{12}}\)

\(\sigma_{20} = \sqrt{\frac{399}{12}}\)

Next, perform the division:

\(\frac{399}{12} = 33.25\)

So, the standard deviation is the square root of 33.25:

\(\sigma_{20} = \sqrt{33.25}\)

Calculating the square root:

\(\sqrt{33.25} \approx 5.766\)

Comparing with Options

Our calculated value for the standard deviation of the first 20 natural numbers using the standard formula is approximately 5.766.

Let's look at the given options:

  • Option 1: 7.525
  • Option 2: 5.845
  • Option 3: 3.028 (This is the given SD for the first 10 natural numbers)
  • Option 4: 9.325

Comparing our result \(5.766\) with the options, we see that Option 2 (\(5.845\)) is the closest value provided among the choices.

While our precise calculation using the standard population standard deviation formula for the first n natural numbers gives approximately 5.766, the option 5.845 is provided as the intended answer and is the closest choice.

Revision Table: Key Concepts in Standard Deviation

ConceptDescriptionFormula for first \(n\) natural numbers (Population)
Mean (\(\mu\))The average of the numbers.\(\frac{n+1}{2}\)
Variance (\(\sigma^2\))The average of the squared differences from the mean.\(\frac{n^2 - 1}{12}\)
Standard Deviation (\(\sigma\))The square root of the variance, measuring the spread of data.\(\sqrt{\frac{n^2 - 1}{12}}\)

Additional Information: Understanding Standard Deviation

The standard deviation is a crucial measure of the dispersion or spread of a data set. A higher standard deviation indicates that the data points are more spread out from the mean, while a lower standard deviation indicates that the data points are clustered closer to the mean.

For the first n natural numbers, the data points are uniformly distributed integers. The formulas for mean, variance, and standard deviation reflect this specific distribution.

The formula \(\sigma = \sqrt{\frac{n^2 - 1}{12}}\) is derived from the definition of population variance \(\sigma^2 = \frac{\sum (x_i - \mu)^2}{n}\) by substituting \(x_i = i\), \(\mu = \frac{n+1}{2}\), and performing the necessary summation and algebraic simplification. This formula applies specifically to the set of first natural numbers $\{1, 2, \dots, n\}$.

In statistics, there is also the sample standard deviation (s), which uses a slightly different denominator (\(n-1\)) in the variance calculation. However, for theoretical problems involving the set of the first n natural numbers as the entire population, the population standard deviation formula is typically used.

Was this answer helpful?

Similar Questions

  1. The fourth central moment of a mesokurtic distribution is 243. Its standard deviation is:

  2. The variance of degenerate random variable is:

  3. If n 1= 10 and n 2= 5 are the sizes, \(\rm\bar{x}_1\)  = 7 and  \(\rm\bar{x}_2\)  = 4 are the means and σ 1= 1 and σ 2= 1 are the standard deviations of two series of data. If combined mean  \(\rm\bar{x}\)  = 6, then the variance of the combined series with size n 1+ n 2is equal to:

  4. If the sum of 10 observations is 12 and the sum of their squares is 18, then the standard deviation is:

  5. Among these options, which one is NOT an example of relative measure of dispersion?


Important Questions from Variance and Standard Deviation

  1. Mean of 100 observations is 50 and standard deviation is 10. If 5 is added to each observation, then what will be the new mean and new standard deviation respectively?

  2. When sampling is done without replacement then standard error of mean is:

  3. Consider a population that is finite, and sampling is with replacement. If the variance of the population is 2176.8 with a sample size of 16, then the variance of the sampling distribution of means is:

  4. If \(\rm \displaystyle \sum_{i = 1}^{10}x_i = 110\)  and  \(\rm \displaystyle \sum_{i = 1}^{10}x_i^2 = 1540\)   then what is the variance?

  5. The sum of deviations of n numbers from 10 and 20 are p and q respectively. If (p - q)2 = 10000, then what is the value of n?

Need Expert Advice?
Upcoming Exams
SSC CGL
September 30, 2026
UPSSSC PET
October 23, 2026
Test Series
SSC CGL img
SSC
SSC CGL (Tier I + Tier II) 2026 Mock Test Series - Latest Pattern
2503 Tests 6 Tests Free
5393 Attempts
4.2(868)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App