Mean of 100 observations is 50 and standard deviation is 10. If 5 is added to each observation, then what will be the new mean and new standard deviation respectively?
55, 10
The question asks about how the mean and standard deviation of a dataset change when a constant value is added to each observation. This is a fundamental concept in statistics related to the properties of these measures.
We are given the following information for a set of 100 observations:
We need to find the new mean and new standard deviation if 5 is added to each of the 100 observations.
Let \(x_1, x_2, \dots, x_{100}\) be the original 100 observations. The mean is given by \(\bar{x} = \frac{\sum x_i}{n}\). The standard deviation is given by \(\sigma = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n}}\).
When a constant, say 'c', is added to each observation, the new observations become \(x'_i = x_i + c\). In this problem, the constant \(c = 5\). So, the new observations are \(x'_i = x_i + 5\).
The new mean, \(\bar{x}'\), is the sum of the new observations divided by the number of observations:
\(\bar{x}' = \frac{\sum x'_i}{n} = \frac{\sum (x_i + c)}{n}\)
We can split the sum:
\(\bar{x}' = \frac{\sum x_i + \sum c}{n}\)
The sum of a constant 'c' repeated 'n' times is \(n \times c\). So, \(\sum c = nc\).
\(\bar{x}' = \frac{\sum x_i + nc}{n} = \frac{\sum x_i}{n} + \frac{nc}{n}\)
We know that \(\frac{\sum x_i}{n}\) is the original mean \(\bar{x}\). So,
\(\bar{x}' = \bar{x} + c\)
This shows that if a constant 'c' is added to each observation, the new mean is the original mean plus 'c'.
Using the given values:
The new mean is 55.
The standard deviation measures the spread or dispersion of the data points around the mean. The formula for the new standard deviation, \(\sigma'\), based on the new observations \(x'_i\) and the new mean \(\bar{x}'\), is:
\(\sigma' = \sqrt{\frac{\sum (x'_i - \bar{x}')^2}{n}}\)
Substitute \(x'_i = x_i + c\) and \(\bar{x}' = \bar{x} + c\):
\(\sigma' = \sqrt{\frac{\sum ((x_i + c) - (\bar{x} + c))^2}{n}}\)
Simplify the term inside the parenthesis:
\((x_i + c) - (\bar{x} + c) = x_i + c - \bar{x} - c = x_i - \bar{x}\)
So, the formula for the new standard deviation becomes:
\(\sigma' = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n}}\)
This is exactly the formula for the original standard deviation, \(\sigma\).
\(\sigma' = \sigma\)
This shows that if a constant 'c' is added to each observation, the standard deviation remains unchanged.
Using the given values:
The new standard deviation is 10.
When 5 is added to each observation:
We need to find the option that shows the new mean and new standard deviation respectively.
Let's look at the options:
| Option | New Mean | New Standard Deviation | Matches Our Result? |
|---|---|---|---|
| 1 | 50 | 10 | No |
| 2 | 50 | 15 | No |
| 3 | 55 | 10 | Yes |
| 4 | 55 | 15 | No |
Option 3 matches our calculated new mean (55) and new standard deviation (10).
| Operation on each observation | Effect on Mean | Effect on Standard Deviation |
|---|---|---|
| Adding a constant (c) | New Mean = Original Mean + c | New Standard Deviation = Original Standard Deviation |
| Subtracting a constant (c) | New Mean = Original Mean - c | New Standard Deviation = Original Standard Deviation |
| Multiplying by a constant (k) | New Mean = k \(\times\) Original Mean | New Standard Deviation = |k| \(\times\) Original Standard Deviation |
| Dividing by a constant (k, k\(\neq\)0) | New Mean = Original Mean / k | New Standard Deviation = Original Standard Deviation / |k| |
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