The mean and standard deviation (SD) of marks obtained by 50 students of a class in 4 subjects are given below :Subject Mathematics Physics Chemistry Biology Mean Marks 40 28 38 36 SD 15 12 14 16
Which one of the following subjects shows highest variability of marks ?
Biology
To determine which subject shows the highest variability of marks, we need to compare the relative variability rather than just the standard deviation, especially since the mean marks for the subjects are different. The standard deviation measures the absolute dispersion of data, but the Coefficient of Variation (CV) measures the relative dispersion with respect to the mean. It is calculated as the ratio of the standard deviation to the mean, usually expressed as a percentage.
The Coefficient of Variation is a statistical measure used to compare the degree of variation between data series, even if their means are drastically different. A higher CV indicates greater variability relative to the mean.
The formula for Coefficient of Variation is:
\(\text{CV} = \frac{\text{Standard Deviation (SD)}}{\text{Mean}} \times 100\%\)
The question provides the mean marks and standard deviation for 4 subjects:
| Subject | Mean Marks | Standard Deviation (SD) |
|---|---|---|
| Mathematics | 40 | 15 |
| Physics | 28 | 12 |
| Chemistry | 38 | 14 |
| Biology | 36 | 16 |
Let's calculate the Coefficient of Variation for each subject:
\(\text{CV}_{\text{Mathematics}} = \frac{15}{40} \times 100\%\)
\(\text{CV}_{\text{Mathematics}} = 0.375 \times 100\%\)
\(\text{CV}_{\text{Mathematics}} = 37.5\%\)
\(\text{CV}_{\text{Physics}} = \frac{12}{28} \times 100\%\)
\(\text{CV}_{\text{Physics}} \approx 0.42857 \times 100\%\)
\(\text{CV}_{\text{Physics}} \approx 42.86\%\)
\(\text{CV}_{\text{Chemistry}} = \frac{14}{38} \times 100\%\)
\(\text{CV}_{\text{Chemistry}} \approx 0.36842 \times 100\%\)
\(\text{CV}_{\text{Chemistry}} \approx 36.84\%\)
\(\text{CV}_{\text{Biology}} = \frac{16}{36} \times 100\%\)
\(\text{CV}_{\text{Biology}} \approx 0.44444 \times 100\%\)
\(\text{CV}_{\text{Biology}} \approx 44.44\%\)
Now, let's compare the calculated Coefficient of Variation for all subjects:
The subject with the highest Coefficient of Variation shows the highest relative variability in marks.
Comparing the CV values, Biology has the highest CV (44.44%).
Based on the calculation of the Coefficient of Variation, Biology shows the highest variability of marks among the given subjects, relative to its mean marks.
| Term | Definition | Use Case | Calculation |
|---|---|---|---|
| Standard Deviation (SD) | Measures the average distance of data points from the mean. | Comparing variability when means are similar or in a single dataset. | Square root of variance. |
| Coefficient of Variation (CV) | Measures relative variability with respect to the mean. | Comparing variability across datasets with different means. | (SD / Mean) \(\times\) 100% |
Understanding data dispersion or variability is crucial in statistics. Besides Standard Deviation and Coefficient of Variation, other measures of dispersion include:
When analyzing marks or test scores, variability can indicate how spread out the scores are. High variability might suggest a wide range of student performance, while low variability might indicate that most students performed similarly.
Mean of 100 observations is 50 and standard deviation is 10. If 5 is added to each observation, then what will be the new mean and new standard deviation respectively?
If \(\rm \displaystyle \sum_{i = 1}^{10}x_i = 110\) and \(\rm \displaystyle \sum_{i = 1}^{10}x_i^2 = 1540\) then what is the variance?
The sum of deviations of n numbers from 10 and 20 are p and q respectively. If (p - q)2 = 10000, then what is the value of n?
In any discrete series (when all values are not same) if x represent mean deviation about mean and y represent standard deviation, then which one of the following is correct?
If V is the variance and M is the mean of first 15 natural numbers, then what is V + M 2equal to?
What is the coefficient of variation of marks in Mathematics ?
Arithmetic mean of 10 observations is 60 and sum of squares of deviations from 50 is 5000. What is the standard deviation of the observations?
Consider the following statements:
1) If 10 is added to each entry on a list, then the average increases by 10
2) IF 10 is added to each entry on a list, then the standard deviation increases by 10
3) if each entry on a list is doubled then the average doubles
What of the above statements are correct?
The variance of 25 observations is 4. If 2 is added to each observation, then the new variance of the resulting observations is
An analysis of monthly wages paid to the workers in two firms A and B belonging to the same industry gives the following result:
Firm A | Firm B | |
Number of workers | 500 | 600 |
Average monthly wage | Rs. 1860 | Rs. 1750 |
Variance of distribution of wages | 81 | 100 |
The average of monthly wage and variance of distribution of wages of all the workers in the firms A and B taken together are
Mean of 100 observations is 50 and standard deviation is 10. If 5 is added to each observation, then what will be the new mean and new standard deviation respectively?
When sampling is done without replacement then standard error of mean is:
Consider a population that is finite, and sampling is with replacement. If the variance of the population is 2176.8 with a sample size of 16, then the variance of the sampling distribution of means is:
If \(\rm \displaystyle \sum_{i = 1}^{10}x_i = 110\) and \(\rm \displaystyle \sum_{i = 1}^{10}x_i^2 = 1540\) then what is the variance?
The sum of deviations of n numbers from 10 and 20 are p and q respectively. If (p - q)2 = 10000, then what is the value of n?