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Question

The speeds of two motorcyclists are in the ratio 5 : 3. If the slower motorcyclist has a 24 km head start, and his speed is 12 km/h, how far (in km) will the faster motorcyclist travel to overtake him?

This question was previously asked in
SSC CGL 2025 Tier 1 Question Paper (25-Sep-2025) (Shift 3)
The correct answer is
60 km

To find the distance the faster motorcyclist travels to overtake the slower one, we need to determine their speeds and the time it takes to close the gap.

Step 1: Calculate the Faster Motorcyclist's Speed

The speeds are in the ratio $5:3$. The slower motorcyclist's speed ($S_{slow}$) is 12 km/h. Let the faster motorcyclist's speed be $S_{fast}$.

We set up the proportion:

$ \frac{S_{fast}}{S_{slow}} = \frac{5}{3} $

Substitute the known speed:

$ \frac{S_{fast}}{12 \text{ km/h}} = \frac{5}{3} $

Solve for $S_{fast}$:

$ S_{fast} = \frac{5}{3} \times 12 \text{ km/h} $ $ S_{fast} = 5 \times 4 \text{ km/h} $ $ S_{fast} = 20 \text{ km/h} $

The faster motorcyclist travels at 20 km/h.

Step 2: Calculate the Time to Overtake

The slower motorcyclist has a 24 km head start. The faster motorcyclist needs to close this distance.

The relative speed at which the faster motorcyclist catches up is the difference between their speeds:

$ S_{relative} = S_{fast} - S_{slow} $ $ S_{relative} = 20 \text{ km/h} - 12 \text{ km/h} $ $ S_{relative} = 8 \text{ km/h} $

The time required to cover the 24 km gap is calculated using:

$ \text{Time} = \frac{\text{Distance Gap}}{S_{relative}} $ $ \text{Time} = \frac{24 \text{ km}}{8 \text{ km/h}} $ $ \text{Time} = 3 \text{ hours} $

It will take 3 hours for the faster motorcyclist to overtake the slower one.

Step 3: Calculate the Distance Travelled by the Faster Motorcyclist

To find how far the faster motorcyclist travels, multiply their speed by the time taken to overtake:

$ \text{Distance} = S_{fast} \times \text{Time} $ $ \text{Distance} = 20 \text{ km/h} \times 3 \text{ hours} $ $ \text{Distance} = 60 \text{ km} $

The faster motorcyclist travels 60 km to overtake the slower motorcyclist.

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Important Questions from Relative Speed

  1. The driver of a car, which is travelling at a speed of 75 km/h, locates a bus 80 m ahead of him, travelling in the same direction. After 15 seconds, he finds that the bus is 40 m behind the car. What is the speed of the bus (in km/h)?

  2. The distance between two station A and B is 800 km. A train X starts from A and moves towards B at 40 km/h and another trains Y starts from B and moves towards A at 60 km/h. how far from A will they cross each other?

  3. A and B are travelling towards each other from the points P and Q respectively. After crossing each other, A and B take \(6\frac{1}{8}\) hours and 8 hours, respectively, to reach their destinations Q and P, respectively. If the speed of B is 16.8 km/h, then the speed (in km/hr) of A is: 

  4. A train leaves station A at 8 am and reaches station B at 12 noon. A car leaves station B at 8:30 am and reaches station A at the same time when the train reaches station B. At what time do they meet?

  5. A and B start moving towards each other from places X and Y respectively, at the same time. The speed of A is 20% more than that of B. After meeting on the way, A and B take \(2\frac{1}{2}\) hours and x hours now to reach Y and X respectively. What is the value of x?

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