Ajay and Vijay start from the same point and walk at 4 km/h and 5 km/h respectively, in the same direction. What will be the distance between them after 2 hours?
This problem involves finding the separation distance between two individuals, Ajay and Vijay, after a specific time, given their different speeds but the same starting point and direction.
When two objects move in the same direction, their relative speed is the difference between their individual speeds. This relative speed tells us how quickly the distance between them is changing.
First, find the relative speed of Vijay with respect to Ajay:
Relative speed ($s_{rel}$) = Vijay's speed - Ajay's speed
$s_{rel} = s_V - s_A$ $s_{rel} = 5 \text{ km/h} - 4 \text{ km/h}$ $s_{rel} = 1 \text{ km/h}$This means Vijay gains 1 km on Ajay every hour.
Now, calculate the distance between them after 2 hours using the formula: Distance = Relative Speed × Time
$d = s_{rel} \times t$ $d = 1 \text{ km/h} \times 2 \text{ h}$ $d = 2 \text{ km}$Alternatively, we can calculate the distance each person covers individually and then find the difference.
The distance between them is the difference between the distances they covered:
$d = d_V - d_A$ $d = 10 \text{ km} - 8 \text{ km}$ $d = 2 \text{ km}$Both methods confirm that the distance between Ajay and Vijay after 2 hours is 2 km.
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