The specific latent heat of fusion of ethyl alcohol is 100 Jg⁻¹. Find the heat absorbed (in J) by 2.25 g of ethyl alcohol when it melts at its melting point of -114°C.
225
Heat absorbed during melting at a constant temperature is given by Q = m × L, where L is the specific latent heat of fusion.
m = 2.25 g and L = 100 J/g
Q = 2.25 × 100
= 225 J
Check: 225 ÷ 2.25 = 100 J/g, matching the latent heat value. The melting temperature does not change the result.
Hence, 225.
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