The problem asks for the heat generated by an electric iron given its resistance, current, and the time duration.
The heat generated by an electrical appliance is calculated using Joule's law of heating:
$H = I^2 R t$
Where:
Substitute the given values into the formula:
$H = (5\text{ A})^2 \times (20\ \Omega) \times (30\text{ s})$
First, calculate the square of the current:
$I^2 = (5)^2 = 25\text{ A}^2$
Now, multiply this by the resistance and time:
$H = 25\text{ A}^2 \times 20\ \Omega \times 30\text{ s}$
$H = 500 \times 30\text{ J}$
$H = 15000\text{ J}$
Expressing this in scientific notation:
$H = 1.5 \times 10^4\text{ J}$
The heat flow in 30 seconds is $1.5 \times 10^4\text{ J}$.
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