The smallest perfect square number divisible by each of 6 and 12 is:
36
The goal is to find the smallest number that is both a perfect square and divisible by both 6 and 12.
First, find the LCM of 6 and 12. The LCM is the smallest number divisible by both numbers.
So, 12 is the smallest number divisible by both 6 and 12.
Next, check if the LCM (12) is a perfect square. A perfect square has prime factors with even exponents.
To find the smallest perfect square divisible by 12, we need to adjust the prime factorization of 12 ($2^2 \times 3^1$) so all exponents are even. We need to multiply by $3^1$ (which is 3) to make the exponent of 3 even.
The number 36 is a perfect square ($6^2$) and is divisible by both 6 ($36 \div 6 = 6$) and 12 ($36 \div 12 = 3$).
The smallest perfect square number divisible by each of 6 and 12 is 36.
A frog was at the bottom of an 80 m deep well. It attempted to come out of it by jumping. In each jump, it covered 1.15 m but slipped down by 0.75 m. The number of jumps after which it would be out of the well is:
The L.C.M. of two different numbers are 30. Which of the following cannot be their H.C.F.?
Which is the least four-digit number which when divided by 5, 6 and 8 leaves remainder 2 in each case?
A frog was at the bottom of an 80 m deep well. It attempted to come out of it by jumping. In each jump, it covered 1.15 m but slipped down by 0.75 m. The number of jumps after which it would be out of the well is:
The L.C.M. of two different numbers are 30. Which of the following cannot be their H.C.F.?
Which is the least four-digit number which when divided by 5, 6 and 8 leaves remainder 2 in each case?