The six-digit number 7x1yyx is a multiple of 33 for non-zero digits x and y. Which of the following could be a possible value of (x + y)?
5
The correct answer is 5.
Alternating sum: 4-7+7-1+4-7 = -3+6-3 = 0 (divisible by 11). 741774 is divisible by 33. All three cases result in a number that is a multiple of 33, with x and y being non-zero digits. The possible values for (x+y) are indeed 5, 8, and 11.
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