Which of the following numbers will completely divide (661 + 662 + 663 + 664)?
7
Factor the common term:
\(6^{61}+6^{62}+6^{63}+6^{64}=6^{61}(1+6+6^{2}+6^{3})=6^{61}(1+6+36+216)=6^{61}\times 259\)
Now \(259=7\times 37\), so the sum is divisible by 7. Among the given options only 7 divides the expression.
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