Factorize the given algebraic expression. x 3+ 27y 3+ 64z 3- 36xyz
The correct answer is (x + 3y + 4z) (x 2 + 9y 2 + 16z 2 - 3xy - 12yz - 4xz).
For example, to factorize $(\text{x}-\text{y})^3 + (\text{y}-\text{z})^3 + (\text{z}-\text{x})^3$, we can observe that $(\text{x}-\text{y}) + (\text{y}-\text{z}) + (\text{z}-\text{x}) = \text{x}-\text{y}+\text{y}-\text{z}+\text{z}-\text{x} = 0$. So, the factorization is $3(\text{x}-\text{y})(\text{y}-\text{z})(\text{z}-\text{x})$. Recognizing the standard forms of algebraic expressions and knowing the corresponding identities is crucial for efficient factorization. Always try to see if the expression fits one of the known identity patterns before attempting other factorization methods.
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