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Question

What is the total number of odd and even divisors of 120, respectively?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
4, 12

120 Prime Factorization

First, find the prime factorization of the number 120.

$120 = 2^3 \\times 3^1 \\times 5^1$

Total Divisors Calculation

The total number of divisors is calculated by adding 1 to each exponent in the prime factorization and multiplying the results.

Number of divisors = $(3+1) \\times (1+1) \\times (1+1) = 4 \\times 2 \\times 2 = 16$

Odd Divisors Count

To find the number of odd divisors, consider only the odd prime factors (3 and 5). The power of 2 is excluded.

Number of odd divisors = $(1+1) \\times (1+1) = 2 \\times 2 = 4$

Even Divisors Count

The number of even divisors is the total number of divisors minus the number of odd divisors.

Number of even divisors = Total divisors - Odd divisors

Number of even divisors = $16 - 4 = 12$

Final Answer Derivation

The number of odd divisors is 4, and the number of even divisors is 12.

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