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Question

How many factors does the number 12288 have?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
26

Finding Factors of 12288

To find the total number of factors for any integer, we first determine its prime factorization.

The prime factorization of a number $N$ is expressed as $N = p_1^{a_1} \times p_2^{a_2} \times \dots \times p_k^{a_k}$, where $p_i$ are distinct prime numbers and $a_i$ are their positive integer exponents.

The total number of factors of $N$ is calculated using the formula: Number of Factors = $(a_1+1)(a_2+1)\dots(a_k+1)$.

Prime Factorization of 12288

Let's find the prime factors of 12288:

  • $12288 \div 2 = 6144$
  • $6144 \div 2 = 3072$
  • $3072 \div 2 = 1536$
  • $1536 \div 2 = 768$
  • $768 \div 2 = 384$
  • $384 \div 2 = 192$
  • $192 \div 2 = 96$
  • $96 \div 2 = 48$
  • $48 \div 2 = 24$
  • $24 \div 2 = 12$
  • $12 \div 2 = 6$
  • $6 \div 2 = 3$
  • $3 \div 3 = 1$

The prime factorization of 12288 is $2^{12} \times 3^1$.

Calculating the Number of Factors

Using the prime factorization $12288 = 2^{12} \times 3^1$, we identify the exponents:

  • Exponent of prime factor 2 ($a_1$) is 12.
  • Exponent of prime factor 3 ($a_2$) is 1.

Apply the formula for the number of factors:

Number of Factors = $(12 + 1) \times (1 + 1)$

Number of Factors = $13 \times 2$

Number of Factors = $26$

Thus, the number 12288 has 26 factors.

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