The simple interest on a certain sum is one-fourth of the sum. If the number of years and the rate of annual interest are numerically equal, then the number of years is
5
Simple interest is a basic concept in finance where interest is calculated only on the principal amount. It's a quick and easy method of calculating interest.
The question involves a scenario where the simple interest earned on a sum of money has a specific relationship with the principal sum, and the rate of interest is numerically equal to the time period in years. We need to find the number of years.
Let's break down the information given in the problem:
Our goal is to find the value of the number of years, T.
The standard formula for calculating simple interest is:
\[ SI = \frac{P \times R \times T}{100} \]Where:
We are given two key pieces of information to use with the simple interest formula:
Let's substitute these conditions into the simple interest formula:
We have \(SI = \frac{P \times R \times T}{100}\).
Substitute \(SI = \frac{1}{4} P\):
\[ \frac{1}{4} P = \frac{P \times R \times T}{100} \]We are also given that the rate \(R\) and the time \(T\) are numerically equal. Let's assume \(R = T = x\), where \(x\) is the numerical value we need to find.
Substitute \(R = x\) and \(T = x\) into the equation:
\[ \frac{1}{4} P = \frac{P \times x \times x}{100} \] \[ \frac{1}{4} P = \frac{P \times x^2}{100} \]Assuming the principal sum \(P\) is not zero (which must be the case to earn interest), we can cancel \(P\) from both sides of the equation:
\[ \frac{1}{4} = \frac{x^2}{100} \]Now, we need to solve for \(x\). Multiply both sides by 100:
\[ x^2 = \frac{100}{4} \] \[ x^2 = 25 \]To find \(x\), take the square root of both sides:
\[ x = \sqrt{25} \]Since time and rate must be positive values in this context, we take the positive square root:
\[ x = 5 \]We defined \(x\) such that \(R = x\) and \(T = x\). Therefore, the rate of interest is 5% and the number of years is 5.
The question asks for the number of years, which is \(T\). We found \(T = x = 5\).
Let's check our answer. Assume the principal \(P = 100\). If the rate is 5% and the time is 5 years, the simple interest would be:
\[ SI = \frac{100 \times 5 \times 5}{100} = \frac{2500}{100} = 25 \]Is this simple interest equal to one-fourth of the principal? One-fourth of the principal (\(P=100\)) is \(\frac{1}{4} \times 100 = 25\). Yes, it is. Also, the rate (5%) is numerically equal to the number of years (5). Our calculation is correct.
When the simple interest is one-fourth of the principal and the number of years is numerically equal to the annual rate of interest, the number of years is 5.
| Given Condition 1 | Mathematical Expression |
|---|---|
| Simple Interest is one-fourth of the Principal | \(SI = \frac{1}{4} P\) |
| Number of Years is numerically equal to Rate | \(T = R\) |
| Simple Interest Formula | \(SI = \frac{P \times R \times T}{100}\) |
|---|---|
| Substitution using conditions | \(\frac{1}{4} P = \frac{P \times T \times T}{100}\) (using \(R=T\)) |
| Simplification | \(\frac{1}{4} = \frac{T^2}{100}\) |
| Solving for \(T^2\) | \(T^2 = \frac{100}{4} = 25\) |
| Solving for \(T\) | \(T = \sqrt{25} = 5\) years |
| Concept | Description |
|---|---|
| Principal (P) | The initial amount of money invested or borrowed. |
| Rate (R) | The annual percentage at which interest is calculated. |
| Time (T) | The duration for which the money is invested or borrowed, usually in years. |
| Simple Interest (SI) | Interest calculated only on the principal amount. Formula: \(\frac{P \times R \times T}{100}\). |
It's helpful to understand the difference between simple interest and compound interest.
Understanding these differences is crucial for solving various financial math problems. Simple interest problems are generally more straightforward as they involve a linear calculation of interest over time.
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