If a sum of money at a certain rate of simple interest per year doubles in 5 years and at a different rate of simple interest per year becomes three times in 12 years, then the difference in the two rates of simple interest per year is
10/3%
This problem involves two scenarios where a sum of money grows under simple interest, but at different rates and over different periods. We need to find the difference between these two simple interest rates.
Simple interest is calculated only on the initial principal amount. The formula for Simple Interest (SI) is:
\[ \text{SI} = \frac{P \times R \times T}{100} \]
Where:
The total Amount (A) after T years is the Principal plus the Simple Interest:
\[ A = P + \text{SI} \]
In the first scenario, let the principal be P. The amount becomes double the principal, which is 2P, in 5 years. The simple interest earned in this case is the difference between the amount and the principal.
Using the simple interest formula:
\[ \text{SI}_1 = \frac{P \times R_1 \times T_1}{100} \]
Substituting the values:
\[ P = \frac{P \times R_1 \times 5}{100} \]
We can cancel P from both sides (assuming P > 0):
\[ 1 = \frac{R_1 \times 5}{100} \]
Now, solve for R1:
\[ R_1 \times 5 = 100 \]
\[ R_1 = \frac{100}{5} \]
\[ R_1 = 20\% \]
So, the first simple interest rate is 20% per year.
In the second scenario, the principal is P. The amount becomes three times the principal, which is 3P, in 12 years. The simple interest earned here is the difference between this amount and the principal.
Using the simple interest formula:
\[ \text{SI}_2 = \frac{P \times R_2 \times T_2}{100} \]
Substituting the values:
\[ 2P = \frac{P \times R_2 \times 12}{100} \]
Cancel P from both sides (assuming P > 0):
\[ 2 = \frac{R_2 \times 12}{100} \]
Now, solve for R2:
\[ R_2 \times 12 = 2 \times 100 \]
\[ R_2 \times 12 = 200 \]
\[ R_2 = \frac{200}{12} \]
Simplify the fraction:
\[ R_2 = \frac{100}{6} \]
\[ R_2 = \frac{50}{3}\% \]
So, the second simple interest rate is 50/3% per year.
We need to find the difference between the two rates, R1 and R2.
Difference = R1 - R2
\[ \text{Difference} = 20\% - \frac{50}{3}\% \]
To subtract these fractions, we need a common denominator, which is 3. Convert 20% to a fraction with a denominator of 3:
\[ 20 = \frac{20 \times 3}{3} = \frac{60}{3} \]
Now subtract:
\[ \text{Difference} = \frac{60}{3}\% - \frac{50}{3}\% \]
\[ \text{Difference} = \frac{60 - 50}{3}\% \]
\[ \text{Difference} = \frac{10}{3}\% \]
The difference in the two simple interest rates per year is 10/3%.
| Scenario | Principal (P) | Amount (A) | Simple Interest (SI) | Time (T) | Rate (R) |
|---|---|---|---|---|---|
| 1 | P | 2P | P | 5 years | 20% |
| 2 | P | 3P | 2P | 12 years | 50/3 % |
| Concept | Description | Formula/Calculation |
|---|---|---|
| Simple Interest (SI) | Interest calculated only on the principal amount. | \[ \frac{P \times R \times T}{100} \] |
| Amount (A) | Total money after adding interest to principal. | \[ P + \text{SI} \] |
| Rate R1 Calculation | Determined when principal doubles in 5 years. | \[ P = \frac{P \times R_1 \times 5}{100} \implies R_1 = 20\% \] |
| Rate R2 Calculation | Determined when principal triples in 12 years. | \[ 2P = \frac{P \times R_2 \times 12}{100} \implies R_2 = \frac{50}{3}\% \] |
| Difference in Rates | Subtracting R2 from R1. | \[ 20\% - \frac{50}{3}\% = \frac{60}{3}\% - \frac{50}{3}\% = \frac{10}{3}\% \] |
Simple interest is one of the most basic concepts in finance. Here are a few points to note:
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