The total volume of the mixture is $72$ L.
The initial ratio of water to milk is $4 : 5$.
The sum of the ratio parts is $4 + 5 = 9$.
Calculate the quantity of each component:
The initial quantities are $32$ L of water and $40$ L of milk.
Let the amount of milk to be added be $x$ L.
The quantity of water remains constant: $32$ L.
The new quantity of milk will be $(40 + x)$ L.
The target ratio of water to milk is $3 : 6$, which simplifies to $1 : 2$.
Set up the equation based on the target ratio:
$ \frac{\text{Water}}{\text{New Milk}} = \frac{1}{2} $
$ \frac{32}{40 + x} = \frac{1}{2} $
Cross-multiply to solve for $x$:
$ 32 \times 2 = 1 \times (40 + x) $
$ 64 = 40 + x $
Isolate $x$:
$ x = 64 - 40 $
$ x = 24 $
Therefore, $24$ L of milk needs to be added.
My father is presently 25 years older than me. The sum of our ages 5 years ago was 39 years. Find my present age.
Rice worth ₹43/kg and ₹67/kg are mixed with a third variety in the ratio 2 : 1 : 5. If the mixture is worth ₹96/kg, the price (in ₹) of the third variety of rice per kg will be:
42 litres of milk at ₹25 per litre is mixed with 28 litres of milk at ₹40 per litre. Find the average price of the mixture.
15 kg of ₹10 per kg wheat is mixed with 5 kg of another type of wheat to get a mixture costing ₹30 per kg. Find the price (per kg) of the costlier wheat.
If a + b + c = 0, then the value of (a² + b² + 2ab) is equal to: