The total volume of the mixture is $72$ L.
The initial ratio of water to milk is $4 : 5$.
The sum of the ratio parts is $4 + 5 = 9$.
Calculate the quantity of each component:
The initial quantities are $32$ L of water and $40$ L of milk.
Let the amount of milk to be added be $x$ L.
The quantity of water remains constant: $32$ L.
The new quantity of milk will be $(40 + x)$ L.
The target ratio of water to milk is $3 : 6$, which simplifies to $1 : 2$.
Set up the equation based on the target ratio:
$ \frac{\text{Water}}{\text{New Milk}} = \frac{1}{2} $
$ \frac{32}{40 + x} = \frac{1}{2} $
Cross-multiply to solve for $x$:
$ 32 \times 2 = 1 \times (40 + x) $
$ 64 = 40 + x $
Isolate $x$:
$ x = 64 - 40 $
$ x = 24 $
Therefore, $24$ L of milk needs to be added.
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