The ratio of two numbers A and B is 5: 8. If 5 is added to each of A and B, then the ratio becomes 2 : 3. The difference between A and B is:
15
This problem involves working with ratios of two numbers. We are given an initial ratio and a new ratio after a specific value is added to both numbers. Our goal is to find the difference between the original two numbers.
Let the two numbers be represented by A and B.
The initial ratio of A to B is given as 5:8.
This means that for some common factor, let's call it \(x\), we can write the numbers as:
We are told that if 5 is added to each number, A and B, the new ratio becomes 2:3.
So, after adding 5 to both A and B, the new numbers are \(A+5\) and \(B+5\). The new ratio is \((A+5):(B+5) = 2:3\).
We can write this as an equation:
\[ \frac{A+5}{B+5} = \frac{2}{3} \]
Now, we substitute the expressions for A and B in terms of \(x\) into this new ratio equation:
\[ \frac{5x+5}{8x+5} = \frac{2}{3} \]
To solve for \(x\), we can cross-multiply:
\[ 3 \times (5x+5) = 2 \times (8x+5) \]
Let's distribute the numbers on both sides of the equation:
\[ 15x + 15 = 16x + 10 \]
Now, we need to isolate the term with \(x\). We can subtract \(15x\) from both sides:
\[ 15 = 16x - 15x + 10 \]
\[ 15 = x + 10 \]
Finally, subtract 10 from both sides to find the value of \(x\):
\[ 15 - 10 = x \]
\[ 5 = x \]
So, the common factor \(x\) is 5.
Now that we have the value of \(x\), we can find the original numbers A and B using our initial definitions:
The two original numbers are 25 and 40.
The question asks for the difference between A and B. Since B is larger than A, the difference is \(B - A\).
Difference = \(40 - 25\)
Difference = \(15\)
Let's quickly check if adding 5 to 25 and 40 gives the new ratio 2:3.
The new ratio is 30:45. Dividing both numbers by their greatest common divisor, which is 15:
\[ \frac{30}{15} = 2 \]
\[ \frac{45}{15} = 3 \]
The new ratio is 2:3, which matches the information given in the problem. This confirms our values for A and B are correct.
| Description | Value |
|---|---|
| Original Ratio (A:B) | 5:8 |
| Numbers represented as | \(5x\), \(8x\) |
| Numbers after adding 5 | \(5x+5\), \(8x+5\) |
| New Ratio | 2:3 |
| Equation | \(\frac{5x+5}{8x+5} = \frac{2}{3}\) |
| Value of \(x\) | 5 |
| Number A | \(5 \times 5 = 25\) |
| Number B | \(8 \times 5 = 40\) |
| Difference (B - A) | \(40 - 25 = 15\) |
The difference between the two numbers A and B is 15.
| Step | Action | Purpose |
|---|---|---|
| 1 | Represent numbers using ratio and variable (e.g., \(5x, 8x\)) | Introduce a common factor to maintain the initial ratio. |
| 2 | Formulate equation based on new information (adding 5 changes ratio) | Translate the problem statement into a solvable algebraic equation. |
| 3 | Solve the equation for the variable (find \(x\)) | Determine the specific value of the common factor. |
| 4 | Calculate the original numbers using the variable's value | Find the actual numerical values of A and B. |
| 5 | Calculate the required value (difference between A and B) | Answer the specific question asked. |
| 6 | Verify the results | Check if the calculated numbers satisfy all conditions in the problem. |
A ratio is a comparison of two quantities. It can be written as \(a:b\) or \(\frac{a}{b}\), where \(b \neq 0\). Ratios can be simplified by dividing both parts by their greatest common divisor.
A proportion is an equation stating that two ratios are equal. For example, \(\frac{a}{b} = \frac{c}{d}\) is a proportion. Proportion problems can often be solved using cross-multiplication (\(ad = bc\)).
When dealing with ratio problems where a value is added or subtracted from the original quantities, representing the original quantities using a common factor (\(ax, bx\)) is a standard algebraic approach. This allows you to set up an equation based on the new ratio and solve for the common factor.
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