The product of 2 numbers is 1530 and their HCF is 15, then their LCM is
102
To find the Least Common Multiple (LCM) of two numbers when given the product and the Highest Common Factor (HCF), we can use the relationship between LCM, HCF, and the product of two numbers. The formula is:
\(LCM \times HCF = \text{Product of the numbers}\)
Substituting the given values:
- \(LCM \times 15 = 1530\)
- To find the LCM, rearrange the equation: \(LCM = \frac{1530}{15}\)
- Calculate the division: \(1530 \div 15 = 102\)
Thus, the LCM of the two numbers is 102.
To ensure accuracy, it's important to verify that the product, when calculated with the found LCM and given HCF, matches the given product:
- Recalculate the product: \(102 \times 15 = 1530\), which matches the given.
Therefore, the correct answer is confirmed to be 102, which aligns with Option B. The correct choice is indeed 102.
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- What is the least number which, when divided by 7, 12 and 15 leaves 1 as the remainder in each case?
- Three-digit numbers are formed of the form "abc" where all the digits a, b and c are different and b = a + c. Total number of such possible three-digit numbers is
- The sum of the digits of a two-digit number is 10. If 18 is subtracted from it, the digits in the resulting number will be equal. The number is :
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