Difference Between Largest 3 Digit and Smallest 2 Digit Number
The question asks us to find the difference between two specific numbers: the largest possible 3-digit number and the smallest possible 2-digit number.
Identifying the Largest 3-Digit Number
- A 3-digit number uses three place values: hundreds, tens, and ones.
- To make the largest number, we need to use the largest possible digit, which is 9, in each place value.
- Therefore, the largest 3-digit number is 999.
Identifying the Smallest 2-Digit Number
- A 2-digit number uses two place values: tens and ones.
- The smallest digit is 0, but a 2-digit number cannot start with 0.
- So, the smallest possible digit for the tens place is 1.
- For the ones place, we can use the smallest digit, which is 0.
- Therefore, the smallest 2-digit number is 10.
Calculating the Difference
To find the difference, we need to subtract the smallest 2-digit number from the largest 3-digit number.
The calculation is as follows:
Largest 3-digit number - Smallest 2-digit number
Using LaTeX notation:
$999 - 10$
Performing the subtraction:
$999 - 10 = 989$
Final Result
The difference between the largest 3-digit number (999) and the smallest 2-digit number (10) is 989.
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Important Questions from Number System (Notes)
- Which number system uses only digits 0 and 1?
- The sum of the digits of a 2-digit number is 12. When the digits of the number are interchanged, the number becomes 15 more than twice the original number. The original number is:
- What is the least number which, when divided by 7, 12 and 15 leaves 1 as the remainder in each case?
- If $\frac{1}{9!} + \frac{1}{10!} = \frac{x}{11!}$, then the value of x is:
- What will be the output, if we compute the 9's complement of the decimal number 782.54?
