The question asks us to find the smallest possible number that has exactly four digits and can be divided by $9$ without leaving any remainder.
We need to start checking from the smallest 4-digit number, which is $1000$, and find the first one that is divisible by $9$.
A number is divisible by $9$ if the sum of its digits is divisible by $9$. Let's check the numbers starting from $1000$:
We continue checking subsequent numbers:
Since $1008$ is the first 4-digit number we found that satisfies the condition, it is the least 4-digit number exactly divisible by $9$.
We can find the smallest 4-digit number by dividing $1000$ by $9$ and seeing what the remainder is.
Calculate the division:
$1000 \div 9$Performing the division:
$1000 = (9 \times 111) + 1$The quotient is $111$ and the remainder is $1$. This means $1000$ is $1$ more than a multiple of $9$ (which is $999$).
To find the next multiple of $9$ (which will be the smallest 4-digit multiple), we need to add the difference between the divisor ($9$) and the remainder ($1$) to the original number ($1000$).
Difference needed = $9 - \text{remainder} = 9 - 1 = 8$.
The least 4-digit number divisible by $9$ is $1000 + 8 = 1008$.
Both methods confirm that $1008$ is the smallest 4-digit number that is exactly divisible by $9$.
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