The price of fuel decreases by 55%, 35% and 45% in three successive months, but increases by 40% in the fourth month. What is the percentage decrease in the price of fuel in the fourth month as compared to its original price? (Round off to 2 decimal places.)
77.48%
Let the original price be \(100\). Each successive change multiplies the running price by its factor.
Applying the three decreases: \(100 \times 0.45 \times 0.65 \times 0.55\).
\(100 \times 0.45 = 45\); \(45 \times 0.65 = 29.25\); \(29.25 \times 0.55 = 16.0875\).
The fourth-month increase of 40% multiplies by \(1.40\): \(16.0875 \times 1.40 = 22.5225\).
Percentage decrease from the original \(100\) is \(100 - 22.5225 = 77.4775 \approx 77.48\%\).
Hence, the price is about 77.48% lower than the original.
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