The number of signals observed in the proton decoupled $^{13}\text{C}$ NMR spectrum of the following compound is
To determine the number of signals observed in the proton-decoupled \(^{13}\text{C}\) NMR spectrum of the given compound, we need to consider the different carbon environments in the structure.
The structure of the compound shows a bicyclic aromatic system with substituents. The number of signals in a \(^{13}\text{C}\) NMR depends on the number of unique carbon environments. Identical carbon atoms (such as those in equivalent positions) will resonate at the same chemical shift, leading to fewer signals than the actual number of carbon atoms.
Thus, the number of signals in the proton-decoupled \(^{13}\text{C}\) NMR spectrum of the compound is five.
The correct answer is: five.
The organic compound that displays following data is
$^1\text{H}$ NMR ($400\text{ MHz}$): $\delta \ 7.38\text{ (d)}, \ 7.25\text{ (d)}, \ 1.29\text{ (s) ppm}$
The correct match of the circled protons in Column $\text{P}$ with the $^1\text{H}$ NMR chemical shift ($\delta\text{ ppm}$) in Column $\text{Q}$ is
| P | Q | ||
| I | ![]() | A | 6.72 |
| II | ![]() | B | 16.4 |
| III | ![]() | C | -0.61 |
Number of lines in the $^{19}F$ NMR spectrum of $F_2C(Br)-C(Br)Cl_2$ at -120 $^\circ C$ assuming it a mixture of static conformations given below, are
